Python 除非设置了调试标志，否则隐藏回溯
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原文地址: http://stackoverflow.com/questions/27674602/
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Hide traceback unless a debug flag is set
提问by matt wilkie
What is the idiomatic python way to hide traceback errors unless a verbose or debug flag is set?
除非设置了详细或调试标志，否则隐藏回溯错误的惯用 python 方法是什么？
Example code:
示例代码：
their_md5 = 'c38f03d2b7160f891fc36ec776ca4685'
my_md5 = 'c64e53bbb108a1c65e31eb4d1bb8e3b7'
if their_md5 != my_md5:
raise ValueError('md5 sum does not match!')
Existing output now, but only desired when called with foo.py --debug:
现在现有的输出，但只有在调用时才需要foo.py --debug：
Traceback (most recent call last):
File "b:\code\apt\apt.py", line 1647, in <module>
__main__.__dict__[command] (packages)
File "b:\code\apt\apt.py", line 399, in md5
raise ValueError('md5 sum does not match!')
ValueError: md5 sum does not match!
Desired normal output:
所需的正常输出：
ValueError: md5 sum does not match!
Here's a test script: https://gist.github.com/maphew/e3a75c147cca98019cd8
这是一个测试脚本：https: //gist.github.com/maphew/e3a75c147cca98019cd8
采纳答案by Reut Sharabani
The short way is using the sysmodule and use this command:
简短的方法是使用sys模块并使用以下命令：
sys.tracebacklimit = 0
Use your flag to determine the behaviour.
使用您的标志来确定行为。
Example:
例子：
>>> import sys
>>> sys.tracebacklimit=0
>>> int('a')
ValueError: invalid literal for int() with base 10: 'a'
The nicer way is to use and exception hook:
更好的方法是使用和异常钩子：
def exception_handler(exception_type, exception, traceback):
# All your trace are belong to us!
# your format
print "%s: %s" % (exception_type.__name__, exception)
sys.excepthook = exception_handler
Edit:
编辑：
If you still need the option of falling back to the original hook:
如果您仍然需要回退到原始钩子的选项：
def exception_handler(exception_type, exception, traceback, debug_hook=sys.excepthook):
if _your_debug_flag_here:
debug_hook(exception_type, exception, traceback)
else:
print "%s: %s" % (exception_type.__name__, exception)
Now you can pass a debug hook to the handler, but you'll most likely want to always use the one originated in sys.excepthook(so pass nothing in debug_hook). Python binds default arguments oncein definition time (common pitfall...) which makes this always work with the same original handler, before replaced.
现在您可以将调试钩子传递给处理程序，但您很可能希望始终使用起源于的钩子sys.excepthook（因此不要在 中传递任何内容debug_hook）。Python在定义时绑定一次默认参数（常见陷阱...），这使得它在替换之前始终使用相同的原始处理程序。
回答by GingerPlusPlus
try:
pass # Your code here
except Exception as e:
if debug:
raise # re-raise the exception
# traceback gets printed
else:
print("{}: {}".format(type(e).__name__, e))
