javascript 检查数组是否包含（仅）数值
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Check if an array contains (only) numeric values
提问by user2361134
I have arrays such as
我有数组，例如
var arrayVal_Int = ["21", "53", "92", "79"];
var arrayVal_Alpha = ["John", "Christine", "Lucy"];
var arrayVal_AlphaNumeric = ["CT504", "AP308", "NK675"];
- Above
arrayVal_Intshould be considered as (purely) numeric. arrayVal_AlphaandarrayVal_AlphaNumericshould be considered as strings.
- 以上
arrayVal_Int应被视为（纯）数字。 arrayVal_Alpha并且arrayVal_AlphaNumeric应该被视为字符串。
I need to check that in JavaScript.
我需要在 JavaScript 中检查它。
回答by Touffy
Shortest solution, evals to trueif and only if every item is (coercible to) a number:
最短的解决方案，true当且仅当每个项目都是（强制为）一个数字时才求值：
!yourArray.some(isNaN)
回答by A.T.
Using simple JavaScript, you can do something like this:
使用简单的 JavaScript，您可以执行以下操作：
var IsNumericString = ["21","53","92","79"].filter(function(i){
return isNaN(i);
}).length > 0;
It will return true;
它会返回真；
回答by aztlan2k
I had a similar need but wanted to verify if a list contained only integers(i.e., no decimals). Based on the above answers here's a way to do that, which I posting in case anyone needs a similar check.
我有类似的需求，但想验证一个列表是否只包含整数（即，没有小数）。基于上述答案，这里有一种方法可以做到这一点，我发布以防万一有人需要类似的检查。
Thanks @Touffy, for your suggestion.
感谢@Touffy，您的建议。
let x = [123, 234, 345];
let y = [123, 'invalid', 345];
let z = [123, 234.5, 345];
!x.some(i => !Number.isInteger(i)) // true
!y.some(i => !Number.isInteger(i)) // false
!z.some(i => !Number.isInteger(i)) // false
回答by Prawin soni
Try this:
试试这个：
let x = [1,3,46,7,7,8];
let y = [1,354,"fg",4];
let z = [1, 3, 4, 5, "3"];
isNaN(x.join("")) // false
isNaN(y.join("")) // true
isNaN(z.join("")) // false
