如何在 Python 3 中进行 URL 编码？
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How to URL encode in Python 3?
提问by amphibient
I have tried to follow the documentationbut was not able to use urlparse.parse.quote_plus()in Python 3:
我试图按照文档进行操作，但无法urlparse.parse.quote_plus()在Python 3以下内容中使用：
from urllib.parse import urlparse
params = urlparse.parse.quote_plus({'username': 'administrator', 'password': 'xyz'})
I get
我得到
AttributeError: 'function' object has no attribute 'parse'
AttributeError: 'function' 对象没有属性 'parse'
回答by Adam Smith
You misread the documentation. You need to do two things:
你误读了文档。你需要做两件事：
- Quote each key and value from your dictionary, and
- Encode those into a URL
- 引用字典中的每个键和值，以及
- 将它们编码为 URL
Luckily urllib.parse.urlencodedoes both those things in a single step, and that's the function you should be using.
幸运的是urllib.parse.urlencode，这两个功能都可以在一个步骤中完成，而这正是您应该使用的功能。
from urllib.parse import urlencode, quote_plus
payload = {'username':'administrator', 'password':'xyz'}
result = urlencode(payload, quote_via=quote_plus)
# 'password=xyz&username=administrator'
回答by Rich Rajah
For Python 3 you could try using quoteinstead of quote_plus:
对于 Python 3，您可以尝试使用quote代替quote_plus：
import urllib.parse
print(urllib.parse.quote("http://www.sample.com/"))
Result:
结果：
http%3A%2F%2Fwww.sample.com%2F
Or:
或者：
from requests.utils import requote_uri
requote_uri("http://www.sample.com/?id=123 abc")
Result:
结果：
'https://www.sample.com/?id=123%20abc'
回答by rumpel
You're looking for urllib.parse.urlencode
您正在寻找 urllib.parse.urlencode
import urllib.parse
params = {'username': 'administrator', 'password': 'xyz'}
encoded = urllib.parse.urlencode(params)
# Returns: 'username=administrator&password=xyz'
