Bash 脚本语法错误：预期操作数（错误标记为“=”）
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Bash script syntax error: operand expected (error token is "=")
提问by Jürgen K.
What I need to do is to cut a long text file into 10 peaces with same count of lines. Therefore I wrote the following script.
我需要做的是将一个长文本文件以相同的行数切割成 10 个和平区。因此我编写了以下脚本。
#!/usr/bin/bash
filename=""
count=0
file=0
br=$(wc -l $filename | awk '{print }')
let br = $br/10
while read -r line
do
let count = count + 1
name="$line"
echo $name >> file$file.csv
if [ $count = $br ];then
let count=0
let file+=1
fi
done < "$filename"
The scripts produces the following error which I do not understand
脚本产生以下错误，我不明白
cut.sh: line 9: let: =: syntax error: operand expected (error token is "=")
I have read similar topicbut still could not find a solution. Any ideas are welcome. Thanks
我已经阅读了类似的主题，但仍然找不到解决方案。欢迎任何想法。谢谢
回答by heemayl
bashvariable assignment can not have whitespace around =. Drop the spaces around =:
bash变量赋值不能有空格=。删除周围的空格=：
let br=${br}/10
Do the same for all such cases.
对所有此类情况执行相同操作。
回答by Raman Sailopal
Mathematically calculations in bash need to be enclosed in double brackets and so:
bash 中的数学计算需要用双括号括起来，因此：
let count=$(( $count + 1 ))
