java.util.regex.PatternSyntaxException：索引附近的正则表达式模式中的语法错误
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java.util.regex.PatternSyntaxException: Syntax error in regex pattern near index
提问by Gangadhar Nimballi
While splitting to below code
拆分为以下代码时
String s = "12+12";
String[] sr = s.split("+");
I am getting this error in logcat
我在 logcat 中收到此错误
09-03 15:57:22.489: E/AndroidRuntime(22029): FATAL EXCEPTION: main
09-03 15:57:22.489: E/AndroidRuntime(22029): java.util.regex.PatternSyntaxException: Syntax error in regexp pattern near index 1:
09-03 15:57:22.489: E/AndroidRuntime(22029): +
09-03 15:57:22.489: E/AndroidRuntime(22029): ^
09-03 15:57:22.489: E/AndroidRuntime(22029): at java.util.regex.Pattern.compileImpl(Native Method)
09-03 15:57:22.489: E/AndroidRuntime(22029): at java.util.regex.Pattern.compile(Pattern.java:407)
09-03 15:57:22.489: E/AndroidRuntime(22029): at java.util.regex.Pattern.<init>(Pattern.java:390)
09-03 15:57:22.489: E/AndroidRuntime(22029): at java.util.regex.Pattern.compile(Pattern.java:381)
09-03 15:57:22.489: E/AndroidRuntime(22029): at java.lang.String.split(String.java:1832)
09-03 15:57:22.489: E/AndroidRuntime(22029): at java.lang.String.split(String.java:1813)
09-03 15:57:22.489: E/AndroidRuntime(22029): at net.telivo.fiestacancun.ui.calllog.CallLogDetailsFragment.onClick(CallLogDetailsFragment.java:171)
09-03 15:57:22.489: E/AndroidRuntime(22029): at android.view.View.performClick(View.java:4240)
09-03 15:57:22.489: E/AndroidRuntime(22029): at android.view.View$PerformClick.run(View.java:17721)
09-03 15:57:22.489: E/AndroidRuntime(22029): at android.os.Handler.handleCallback(Handler.java:730)
09-03 15:57:22.489: E/AndroidRuntime(22029): at android.os.Handler.dispatchMessage(Handler.java:92)
09-03 15:57:22.489: E/AndroidRuntime(22029): at android.os.Looper.loop(Looper.java:137)
09-03 15:57:22.489: E/AndroidRuntime(22029): at android.app.ActivityThread.main(ActivityThread.java:5103)
09-03 15:57:22.489: E/AndroidRuntime(22029): at java.lang.reflect.Method.invokeNative(Native Method)
09-03 15:57:22.489: E/AndroidRuntime(22029): at java.lang.reflect.Method.invoke(Method.java:525)
09-03 15:57:22.489: E/AndroidRuntime(22029): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:737)
09-03 15:57:22.489: E/AndroidRuntime(22029): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:553)
09-03 15:57:22.489: E/AndroidRuntime(22029): at dalvik.system.NativeStart.main(Native Method)
采纳答案by Maroun
String#splitaccepts a regex.
String#split接受正则表达式。
If you don't want to escape the special char+, you can use Pattern#quote:
如果您不想转义特殊字符+，可以使用Pattern#quote：
Returns a literal pattern Stringfor the specified String.
返回指定字符串的文字模式字符串。
String sr[] = s.split(Pattern.quote("+"));
+will be now treated as a regular character and not a metacharacter.
+现在将被视为常规字符而不是元字符。
回答by sanbhat
+should be escaped, cause +is used to represent one of the quantifiers
+应该被转义，cause+用于表示量词之一
it should be s.split("\\+");
它应该是 s.split("\\+");
回答by Suresh Atta
Since +is a meta character and have a special meaning in regexYou have to escape that meta character
因为+是元字符并且在regex你必须逃避那个元字符中具有特殊含义
String s = "12+12";
String[] sr = s.split("\+");
回答by Tarsem Singh
You should escape the +character.
你应该逃避这个+角色。
String s = "12+12";
String[] sr = s.split("\+");
Escaping a regex is usually done by \, but in Java \is represented as \\.
转义正则表达式通常由 完成\，但在 Java\中表示为\\。
