Linux 有没有办法查看符号链接的实际内容？
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is there a way to see the actual contents of a symlink?
提问by fabio
When you do
当你做
cat some-symlink-to-some-real-file
it shows the contents of the real file, not what is within the symlink itself. Is there a way to see what's actually in it?
它显示真实文件的内容，而不是符号链接本身的内容。有没有办法查看其中的实际内容？
采纳答案by PleaseStand
The ls -lcommand will show you that:
该ls -l命令将显示：
$ ls -l foo
lrwxrwxrwx 1 user group 11 2010-12-31 19:49 foo -> /etc/passwd
Or the readlinkcommand:
$ readlink foo
/etc/passwd
So, the symbolic link foopoints to the path /etc/passwd.
因此，符号链接foo指向 path /etc/passwd。
回答by Eric Fortis
Try
尝试
find . -type l -exec ls -la {} \;
回答by Ben Voigt
You can call the readlink(2)function, which will place the linked-to name into a buffer.
您可以调用该readlink(2)函数，该函数会将链接到的名称放入缓冲区。
Note that the result has a length (stored in the return value) rather than being NUL-terminated. So if you want to use it as a string, append a NUL yourself.
请注意，结果具有长度（存储在返回值中）而不是 NUL 终止。因此，如果您想将其用作字符串，请自己附加一个 NUL。
Most higher-level/scripting languages, such as perl or python, will provide a readlink wrapper that converts to the usual language-appropriate string type, so you won't be bothered by details such as NUL-termination.
大多数高级/脚本语言，例如 perl 或 python，将提供一个 readlink 包装器，可以转换为通常的语言合适的字符串类型，因此您不会被诸如 NUL 终止之类的细节所困扰。
回答by Pavel Patrin
Regarding to man page http://man7.org/linux/man-pages/man7/symlink.7.htmlsymlink is regular file (with special flag) with path to target in its content. So you could copy symlink to FAT partition and read it content there.
关于手册页http://man7.org/linux/man-pages/man7/symlink.7.html符号链接是常规文件（带有特殊标志），其内容中带有目标路径。所以你可以将符号链接复制到 FAT 分区并在那里读取它的内容。
