使用 Youtube API V3 和 PHP 将视频上传到 Youtube

Upload video to Youtube using Youtube API V3 and PHP

提问by jayendrap

I am trying to upload a video to Youtube using PHP. I am using Youtube API v3 and I am using the latest checked out source code of Google API PHP Client library.
I am using the sample code given on
https://code.google.com/p/google-api-php-client/to perform the authentication. The authentication goes through fine but when I try to upload a video I get Google_ServiceExceptionwith error code 500 and message as null.

我正在尝试使用 PHP 将视频上传到 Youtube。我使用的是 Youtube API v3，我使用的是 Google API PHP 客户端库的最新签出源代码。
我正在使用
https://code.google.com/p/google-api-php-client/上给出的示例代码来执行身份验证。身份验证通过得很好，但是当我尝试上传视频时，我收到Google_ServiceException错误代码 500 和消息为空。

I had a look at the following question asked earlier: Upload video to youtube using php client library v3But the accepted answer doesn't describe how to specify file data to be uploaded.
I found another similar question Uploading file with Youtube API v3 and PHP, where in the comment it is mentioned that categoryId is mandatory, hence I tried setting the categoryId in the snippet but still it gives the same exception.

我查看了之前提出的以下问题： 使用 php 客户端库 v3将视频上传到 youtube但是接受的答案没有描述如何指定要上传的文件数据。
我发现了另一个类似的问题Uploading file with Youtube API v3 and PHP，在评论中提到 categoryId 是强制性的，因此我尝试在代码段中设置 categoryId 但它仍然给出相同的异常。

I also referred to the Python code on the the documentation site ( https://developers.google.com/youtube/v3/docs/videos/insert), but I couldn't find the function next_chunk in the client library. But I tried to put a loop (mentioned in the code snippet) to retry on getting error code 500, but in all 10 iterations I get the same error.

我还参考了文档站点 ( https://developers.google.com/youtube/v3/docs/videos/insert)上的 Python 代码，但在客户端库中找不到函数 next_chunk。但是我尝试放置一个循环（在代码片段中提到）来重试获取错误代码 500，但是在所有 10 次迭代中，我都遇到了相同的错误。

Following is the code snippet I am trying:

以下是我正在尝试的代码片段：

$youTubeService = new Google_YoutubeService($client);
if ($client->getAccessToken()) {
    print "Successfully authenticated";
    $snippet = new Google_VideoSnippet();
    $snippet->setTitle = "My Demo title";
    $snippet->setDescription = "My Demo descrition";
    $snippet->setTags = array("tag1","tag2");
    $snippet->setCategoryId(23); // this was added later after refering to another question on stackoverflow

    $status = new Google_VideoStatus();
    $status->privacyStatus = "private";

    $video = new Google_Video();
    $video->setSnippet($snippet);
    $video->setStatus($status);

    $data = file_get_contents("video.mp4"); // This file is present in the same directory as the code
    $mediaUpload = new Google_MediaFileUpload("video/mp4",$data);
    $error = true;
    $i = 0;

    // I added this loop because on the sample python code on the documentation page
    // mentions we should retry if we get error codes 500,502,503,504
    $retryErrorCodes = array(500, 502, 503, 504);
    while($i < 10 && $error) {
        try{
            $ret = $youTubeService->videos->insert("status,snippet", 
                                                   $video, 
                                                   array("data" => $data));

            // tried the following as well, but even this returns error code 500,
            // $ret = $youTubeService->videos->insert("status,snippet", 
            //                                        $video, 
            //                                        array("mediaUpload" => $mediaUpload); 
            $error = false;
        } catch(Google_ServiceException $e) {
            print "Caught Google service Exception ".$e->getCode()
                  . " message is ".$e->getMessage();
            if(!in_array($e->getCode(), $retryErrorCodes)){
                break;
            }
            $i++;
        }
    }
    print "Return value is ".print_r($ret,true);

    // We're not done yet. Remember to update the cached access token.
    // Remember to replace $_SESSION with a real database or memcached.
    $_SESSION['token'] = $client->getAccessToken();
} else {
    $authUrl = $client->createAuthUrl();
    print "<a href='$authUrl'>Connect Me!</a>";
}

Is it something that I am doing wrong?

这是我做错了什么吗？

回答by jayendrap

I was able to get the upload working using the following code:

我能够使用以下代码使上传工作：

if($client->getAccessToken()) {
    $snippet = new Google_VideoSnippet();
    $snippet->setTitle("Test title");
    $snippet->setDescription("Test descrition");
    $snippet->setTags(array("tag1","tag2"));
    $snippet->setCategoryId("22");

    $status = new Google_VideoStatus();
    $status->privacyStatus = "private";

    $video = new Google_Video();
    $video->setSnippet($snippet);
    $video->setStatus($status);

    $error = true;
    $i = 0;

    try {
        $obj = $youTubeService->videos->insert("status,snippet", $video,
                                         array("data"=>file_get_contents("video.mp4"), 
                                        "mimeType" => "video/mp4"));
    } catch(Google_ServiceException $e) {
        print "Caught Google service Exception ".$e->getCode(). " message is ".$e->getMessage(). " <br>";
        print "Stack trace is ".$e->getTraceAsString();
    }
}

回答by Any Day

I realize this is old, but here's the answer off the documentation:

我意识到这已经过时了，但这是文档中的答案：

    // REPLACE this value with the path to the file you are uploading.
    $videoPath = "/path/to/file.mp4";

    $snippet = new Google_Service_YouTube_VideoSnippet();
    $snippet->setTitle("Test title");
    $snippet->setDescription("Test description");
    $snippet->setTags(array("tag1", "tag2"));

    // Numeric video category. See
    // https://developers.google.com/youtube/v3/docs/videoCategories/list 
    $snippet->setCategoryId("22");

    // Set the video's status to "public". Valid statuses are "public",
    // "private" and "unlisted".
    $status = new Google_Service_YouTube_VideoStatus();
    $status->privacyStatus = "public";

    // Associate the snippet and status objects with a new video resource.
    $video = new Google_Service_YouTube_Video();
    $video->setSnippet($snippet);
    $video->setStatus($status);

    // Specify the size of each chunk of data, in bytes. Set a higher value for
    // reliable connection as fewer chunks lead to faster uploads. Set a lower
    // value for better recovery on less reliable connections.
    $chunkSizeBytes = 1 * 1024 * 1024;

    // Setting the defer flag to true tells the client to return a request which can be called
    // with ->execute(); instead of making the API call immediately.
    $client->setDefer(true);

    // Create a request for the API's videos.insert method to create and upload the video.
    $insertRequest = $youtube->videos->insert("status,snippet", $video);

    // Create a MediaFileUpload object for resumable uploads.
    $media = new Google_Http_MediaFileUpload(
        $client,
        $insertRequest,
        'video/*',
        null,
        true,
        $chunkSizeBytes
    );
    $media->setFileSize(filesize($videoPath));


    // Read the media file and upload it chunk by chunk.
    $status = false;
    $handle = fopen($videoPath, "rb");
    while (!$status && !feof($handle)) {
      $chunk = fread($handle, $chunkSizeBytes);
      $status = $media->nextChunk($chunk);
    }

    fclose($handle);

    // If you want to make other calls after the file upload, set setDefer back to false
    $client->setDefer(false);

回答by Gemmu

I also realize this is old, butas I cloned the latest version of php-client from GitHub I ran in to trouble with Google_Service_YouTube_Videos_Resource::insert()-method.

我也意识到这很旧，但是当我从 GitHub 克隆最新版本的 php-client 时，我遇到了Google_Service_YouTube_Videos_Resource::insert()-method 的问题。

I would pass an array with "data" => file_get_contents($pathToVideo)and "mimeType" => "video/mp4"set as an argument for the insert()-method, but I still kept getting (400) BadRequestin return.

我会传递一个数组"data" => file_get_contents($pathToVideo)并"mimeType" => "video/mp4"设置为insert()-method的参数，但我仍然不断收到(400) BadRequest作为回报。

Debugging and reading through Google's code i found in \Google\Service\Resource.phpthere was a check (on lines 179-180) against an array key "uploadType"that would initiate the Google_Http_MediaFielUpload object.

调试和阅读谷歌的代码时，我发现\Google\Service\Resource.php有一个检查（在第 179-180 行）对一个"uploadType"将启动 Google_Http_MediaFielUpload 对象的数组键 。

$part = 'status,snippet';
$optParams = array(
    "data" => file_get_contents($filename),
    "uploadType" => "media",  // This was needed in my case
    "mimeType" => "video/mp4",
);
$response = $youtube->videos->insert($part, $video, $optParams);

If I remember correctly, with version 0.6 of the PHP-api the uploadType argument wasn't needed. This might apply only for the directupload style and not the resumableupload shown in Any Day's answer.

如果我没记错的话，PHP-api 的 0.6 版不需要 uploadType 参数。这可能仅适用于直接上传样式，而不适用于 Any Day 答案中显示的可恢复上传。

回答by Ibrahim Ulukaya

The answer would be using Google_Http_MediaFileUpload through the Google PHP client libraries.

答案是通过Google PHP 客户端库使用 Google_Http_MediaFileUpload 。

Here's the sample code: https://github.com/youtube/api-samples/blob/master/php/resumable_upload.php

这是示例代码：https: //github.com/youtube/api-samples/blob/master/php/resumable_upload.php