有没有更好的方法来确定本地 git 分支是否存在？
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Is there a better way to find out if a local git branch exists?
提问by Manoj Govindan
I am using the following command to find out if a localgit branch with branch-nameexists in my repository. Is this correct? Is there a better way?
我正在使用以下命令来确定我的存储库中是否存在本地git 分支branch-name。这样对吗？有没有更好的办法？
Please note that I am doing this inside a script. For this reason I'd like to use plumbing commandsif possible.
请注意，我在脚本中执行此操作。出于这个原因，如果可能的话，我想使用管道命令。
git show-ref --verify --quiet refs/heads/<branch-name>
# $? == 0 means local branch with <branch-name> exists.
采纳答案by Mark Longair
As far as I know, that's the best way to do it in a script. I'm not sure there's much more to add to that, but there might as well be one answer that just says "That command does everything you want" :)
据我所知，这是在脚本中执行此操作的最佳方法。我不确定还有更多要添加的内容，但也可能有一个答案只是说“该命令可以执行您想要的所有操作”:)
The only thing you might want to be careful of is that branch names can have surprising characters in them, so you may want to quote <branch-name>.
您可能唯一需要注意的是分支名称中可能包含令人惊讶的字符，因此您可能需要引用<branch-name>.
回答by jhuynh
When I search for 'git check if branch exists' on a search engine, this page is the first one I see.
当我在搜索引擎上搜索 'git check if branch exists' 时，这个页面是我看到的第一个页面。
I get what I want, but I'd like to provide a updated answer since the original post was from 2011.
我得到了我想要的，但我想提供一个更新的答案，因为原始帖子是 2011 年的。
git rev-parse --verify <branch_name>
This is essentially the same as the accepted answer, but you don't need type in "refs/heads/"
这与接受的答案基本相同，但您不需要输入“refs/heads/”
回答by Martijn
Almost there.
差不多好了。
Just leave out the --verifyand --quietand you get either the hash if the branch exists or nothing if it doesn't.
只需省略--verifyand --quiet，如果分支存在，您将获得散列，如果不存在，您将获得任何散列。
Assign it to a variable and check for an empty string.
将其分配给变量并检查空字符串。
exists=`git show-ref refs/heads/<branch-name>`
if [ -n "$exists" ]; then
echo 'branch exists!'
fi
回答by Mark Drago
I think you can use git show-branchhere.
我想你可以git show-branch在这里使用。
$ git show-branch --list
[master] test
* [testbranch] test
$ git show-branch testbranch
[testbranch] test
$ echo $?
0
$ git show-branch nonexistantbranch
fatal: bad sha1 reference nonexistantbranch
$ echo $?
128
So, $? == 0 would indicate that the branch exists and you don't have to dig in to the plumbing of refs/heads/ at all. As long as you don't pass -rto show-branch, it will only operate on local branches.
那么，$? == 0 表示分支存在，您根本不必深入研究 refs/heads/ 的管道。只要不传给-rshow-branch，它只会在本地分支上运行。
回答by Razzi Abuissa
I recommend git show-ref --quiet refs/heads/$name.
我推荐git show-ref --quiet refs/heads/$name。
--quietmeans there is no output, which is good because then you can cleanly check exit status.refs/heads/$namelimits to local branches and matches full names (otherwisedevwould matchdevelop)
--quiet意味着没有输出，这很好，因为这样您就可以干净地检查退出状态。refs/heads/$name限制本地分支并匹配全名（否则dev会匹配develop）
Usage in a script:
在脚本中的用法：
if git show-ref --quiet refs/heads/develop; then
echo develop branch exists
fi
回答by Tom Hale
For use in a script:
在脚本中使用：
git show-ref -q --heads <branch-name>
This will exit 0if and only if <branch-name>exists as a local branch.
0当且仅当<branch-name>作为本地分支存在时才会退出。
Example:
例子：
if git show-ref -q --heads <branch-name>; then
echo 'Branch exists'
fi
回答by Tom Hale
Yup, there is one.
是的，有一个。
git rev-parse [<options>] <args>…?
See https://git-scm.com/docs/git-rev-parsewhere you can find the set of arguments and the function.
请参阅https://git-scm.com/docs/git-rev-parse，您可以在其中找到参数集和函数。
git rev-parse --verify <branch-name>
回答by pinkal vansia
On windows batch script it is bit different,
在 Windows 批处理脚本上有点不同，
git rev-parse --verify <branch>
if %ERRORLEVEL% == 0 (
echo "Yes"
) else (
echo "No"
)
回答by Vojtech Vitek
git show-branch <BRANCH-NAME> &>/dev/null && echo yes || echo no
回答by Vojtech Vitek
Let's call it git is_localbranch(you need to add alias in .gitconfig).
让我们调用它git is_localbranch（您需要在 中添加别名.gitconfig）。
Usage:
用法：
$ git is_localbranch BRANCH
Source:
来源：
git branch | grep -w > /dev/null
if [ $? = 0 ]
then
echo "branch exists"
fi
