bash 如何在 Linux 中使用 `find` 命令删除非空目录？
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How can I use the `find` command in Linux to remove non-empty directories?
提问by orokusaki
I have temp directories full of junk that all start with __temp__(e.g. __temp__user_uploads), which I want to delete with a cleanup function. My function attempt is to run:
我有一个充满垃圾的临时目录，它们都以__temp__（例如__temp__user_uploads）开头，我想用清理功能将其删除。我的功能尝试是运行：
find . -name __temp__* -exec rm -rf '{}' \;
If I run the command and there are multiple __temp__directories (__temp__fooand __temp__bar), I get the output:
如果我运行命令并且有多个__temp__目录（__temp__foo和__temp__bar），我会得到输出：
find: __temp__foo: unknown option
If I run the command and there is only 1 __temp__directory (__temp__foo), it is deleted and I get the output:
如果我运行命令并且只有 1 个__temp__目录 ( __temp__foo)，它会被删除并得到输出：
find: ./__temp__foo: No such file or directory
Why doesn't the command work, why is it inconsistent like that, and how can I fix it?
为什么命令不起作用，为什么不一致，我该如何解决？
回答by pilcrow
Use a depth-first search and quote (or escape) the shell metacharacter *:
使用深度优先搜索并引用（或转义）shell 元字符*：
find . -depth -name '__temp__*' -exec rm -rf '{}' \;
Explanation
解释
Without the -depthflag, your findcommand will remove matching filenames and then try to descend into the (now unlinked) directories. That's the origin of the "No such file or directory" in your single __temp__directory case.
如果没有该-depth标志，您的find命令将删除匹配的文件名，然后尝试进入（现在未链接的）目录。这就是您的单__temp__目录案例中“没有这样的文件或目录”的起源。
Without quoting or escaping the *, the shell will expand that pattern, matching several __temp__whateverfilenames in the current working directory. This expansion will confuse find, which is expecting options rather than filenames at that point in its argument list.
不引用或转义*，shell 将扩展该模式，匹配__temp__whatever当前工作目录中的几个文件名。这种扩展会混淆find，它在其参数列表中的那个点期待选项而不是文件名。
