如何在 C++ 中创建类对象的向量?
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How to create a vector of class objects in C++?
提问by Girardi
I am trying to create a simple stack using vector in C++.
我正在尝试使用 C++ 中的向量创建一个简单的堆栈。
Here is the code:
这是代码:
#include <vector>
class Site
{
public:
int i; // site position i (x-axis)
int s; // site state
vector<Site> neighbors;
Site(void);
Site(int ii, int ss);
void AddNeighbor(Site &site);
};
Site::Site()
{
i = -1;
s = -1;
vector<Site> neighbors;
}
Site::Site(int ii, int ss)
{
i = ii;
s = ss;
}
void Site::AddNeighbor(Site &site)
{
neighbors.push_back(site);
}
void testStack()
{
int tot = 600;
vector<Site> myStack();
int i = 0;
while (i < tot)
{
Site site(i, 1);
myStack.push_back(site);
i++;
}
i = 0;
while (i < tot)
{
Site *site = myStack.back();
myStack.pop_back();
cout << site->i << site->s << endl;
i++;
}
}
Compiler errors:
编译器错误:
ising_wolff.cpp: In function ‘void testStack()': ising_wolff.cpp:373:17: error: request for member ‘push_back' in ‘myStack', which is of non-class type ‘std::vector()' myStack.push_back(site); ^ ising_wolff.cpp:380:30: error: request for member ‘back' in ‘myStack', which is of non-class type ‘std::vector()' Site *site = myStack.back(); ^ ising_wolff.cpp:381:17: error: request for member ‘pop_back' in ‘myStack', which is of non-class type ‘std::vector()' myStack.pop_back();
ising_wolff.cpp:在函数“void testStack()”中:ising_wolff.cpp:373:17:错误:在“myStack”中请求成员“push_back”,它是非类类型“std::vector()”myStack .push_back(网站);^ ising_wolff.cpp:380:30:错误:在“myStack”中请求成员“back”,它是非类类型“std::vector()” Site *site = myStack.back(); ^ ising_wolff.cpp:381:17: 错误:在“myStack”中请求成员“pop_back”,它是非类类型“std::vector()”myStack.pop_back();
What do these errors mean?
这些错误是什么意思?
Here are some sites I have looked at:
以下是我看过的一些网站:
1) Creating objects while adding them into vectors
2) push_back causing errors in C
回答by Eric Leschinski
How to create a vector of class objects in C++?
如何在 C++ 中创建类对象的向量?
Start with something simpler so you can get the hang of it.
从更简单的事情开始,这样你就可以掌握它的窍门。
First, create a vector of primitive ints:
首先,创建一个原始整数向量:
#include <vector>
#include <iostream>
using namespace std;
int main(){
vector<int> sites(5);
sites.push_back(5);
for(int x = 0; x < sites.size(); x++){
cout << sites[x];
}
cout << endl;
return 0;
}
Compiling it:
编译它:
g++ -o test test.cpp
Running it:
运行它:
./test
000005
Create a vector of class objects in a similar way as above:
以与上述类似的方式创建类对象的向量:
#include <iostream>
#include <vector>
using namespace std;
class Site {
public:
int i;
};
int main() {
vector<Site> listofsites;
Site *s1 = new Site;
s1->i = 7;
Site *s2 = new Site;
s2->i = 9;
listofsites.push_back(*s1);
listofsites.push_back(*s2);
vector<Site>::iterator it;
for (it = listofsites.begin(); it != listofsites.end(); ++it) {
cout << it->i;
}
return 0;
}
Which should print:
哪个应该打印:
79
回答by Joseph Mansfield
vector<Site> myStack();
This is actually a function declaration. The function is called myStack
and it returns a vector<Site>
. What you actually want is:
这实际上是一个函数声明。该函数被调用myStack
并返回一个vector<Site>
. 你真正想要的是:
vector<Site> myStack;
The type of neighbours
at the moment will store copies of the objects, not references. If you really want to store references, I recommend using a std::reference_wrapper
(rather than using pointers):
目前的类型neighbours
将存储对象的副本,而不是引用。如果你真的想存储引用,我建议使用a std::reference_wrapper
(而不是使用指针):
vector<reference_wrapper<Site>> neighbors;
回答by Lightness Races in Orbit
vector<Site> myStack();
This is wrong. Lose the ()
.
这是错误的。失去()
.
You're declaring a function, not a vector.
你声明的是一个函数,而不是一个向量。
Just write:
写就好了:
vector<Site> myStack;
回答by Rodrigo Saucedo
You could use:
你可以使用:
vector<Site> myStack;
myStack.resize(100); //will create 100 <Site> objects