Python 在模板中使用 Django 设置
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Using Django settings in templates
提问by Roger
I want to be able to put certain configuration information in my settings.py file - things like the site name, site url, etc.
我希望能够在我的 settings.py 文件中放入某些配置信息 - 例如站点名称、站点 url 等。
If I do this, how can I then access those settings in templates?
如果我这样做，我如何才能访问模板中的这些设置？
Thanks
谢谢
采纳答案by Geradeausanwalt
Let's say in your settings.pyfile you have:
让我们在你的settings.py文件中说你有：
SITE_URL='www.mydomain.tld/somewhere/'
SITE_NAME='My site'
If you need that in just one or two views:
如果您只在一两个视图中需要它：
from django.shortcuts import render_to_response
from django.conf import settings
def my_view(request, ...):
response_dict = {
'site_name': settings.SITE_NAME,
'site_url': settings.SITE_URL,
}
...
return render_to_response('my_template_dir/my_template.html', response_dict)
If you need to access these across a lot of apps and/or views, you can write a context processor to save code:
如果您需要在许多应用程序和/或视图中访问这些，您可以编写一个上下文处理器来保存代码：
James has a tutorial on this online.
James 有一个在线教程 。
Some useful information on the when and if of context processors is available on this very site here.
关于何时以及是否context处理器可以用这个非常站点的一些有用的信息 在这里。
Inside your my_context_processors.pyfile you would:
在您的my_context_processors.py文件中，您将：
from django.conf import settings
def some_context_processor(request):
my_dict = {
'site_url': settings.SITE_URL,
'site_name': settings.SITE_NAME,
}
return my_dict
Back in your settings.py, activate it by doing:
回到您的settings.py，通过执行以下操作激活它：
TEMPLATE_CONTEXT_PROCESSORS = (
...
# yours
'my_context_processors.some_context_processor',
)
In your views.py, make a view use it like so:
在您的views.py, 视图中使用它，如下所示：
from django.shortcuts import render_to_response
from django.template import RequestContext
def my_view(request, ...):
response_dict = RequestContext(request)
...
# you can still still add variables that specific only to this view
response_dict['some_var_only_in_this_view'] = 42
...
return render_to_response('my_template_dir/my_template.html', response_dict)
回答by Brian Stoner
If you only need a setting or two for a couple views, Context Processor may be overkill since it will add them to ALL views in your app. But if it's used in a lot of templates, Contest Processor is the way to go.
如果您只需要为几个视图设置一两个，上下文处理器可能会过大，因为它会将它们添加到您应用程序中的所有视图中。但是如果它被用在很多模板中，那么 Contest Processor 是要走的路。
For the simple one off case just pass whatever setting you need from the view to the template:
对于简单的一次性案例，只需将您需要的任何设置从视图传递到模板：
from django.conf import settings
from django.shortcuts import render_to_response
def some_view(request):
val = settings.SAVED_SETTING
return render_to_response("index.html", {
'saved_setting':val
})
And access the setting in your template via:
并通过以下方式访问模板中的设置：
{{ saved_setting }}
回答by Bill Paetzke
If using a class-based view:
如果使用基于类的视图：
#
# in settings.py
#
YOUR_CUSTOM_SETTING = 'some value'
#
# in views.py
#
from django.conf import settings #for getting settings vars
class YourView(DetailView): #assuming DetailView; whatever though
# ...
def get_context_data(self, **kwargs):
context = super(YourView, self).get_context_data(**kwargs)
context['YOUR_CUSTOM_SETTING'] = settings.YOUR_CUSTOM_SETTING
return context
#
# in your_template.html, reference the setting like any other context variable
#
{{ YOUR_CUSTOM_SETTING }}
