php php比较两个关联数组
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php compare two associative arrays
提问by Julian Paolo Dayag
i have these two associative arrays
我有这两个 associative arrays
// the needle array
// 针数组
$a = array(
"who" => "you",
"what" => "thing",
"where" => "place",
"when" => "hour"
);
// the haystack array
// 干草堆数组
$b = array(
"when" => "time",
"where" => "place",
"who" => "you",
"what" => "thing"
);
i want to check if the $ahas a match with the bwith it's exact keyand value
我想检查它是否与它完全$a匹配并且bkeyvalue
and if each key and value from $ahas an exact match in $b.... i want to increment the value of a variable $cby 1 and so on...
并且如果来自的每个键和值$a在$b.... 中具有完全匹配，我想将变量的值增加$c1 等等...
as we've seen from above there 3 possible match...
and supposedly results to increment the value of $cby 3
正如我们从上面看到的那样，有 3 个可能的匹配项......并且据说结果将 的值增加了$c3
$c = "3";
$c = "3";
i hope some genius can help me...
我希望有天才可以帮助我...
回答by hjpotter92
you can look into the php's array_diff_assoc()function or the array_intersect()function.
你可以查看php的array_diff_assoc()函数或者array_intersect()函数。
EDIT
编辑
Here's a sample on counting the matched values:
以下是计算匹配值的示例：
<?php
$a = array(
"who" => "you",
"what" => "thing",
"where" => "place",
"when" => "hour"
);
// the haystack array
$b = array(
"when" => "time",
"where" => "place",
"who" => "you",
"what" => "thing"
);
$c = count(array_intersect($a, $b));
echo $c;
?>
CODEPADlink.
键盘链接。
