从基于 Flask 的 Python 服务器下载文件
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Download a file from a Flask-based Python server
提问by Alexandre D.
I'm trying to make work a code that I found at this URL: http://code.runnable.com/UiIdhKohv5JQAAB6/how-to-download-a-file-generated-on-the-fly-in-flask-for-python
我正在尝试使用我在此 URL 上找到的代码：http: //code.runnable.com/UiIdhKohv5JQAAB6/how-to-download-a-file-generated-on-the-fly-in-flask-蟒蛇
My goal is to be able to download a file on a web browser when the user access to a web service on my Flask-base Python server.
我的目标是当用户访问基于 Flask 的 Python 服务器上的 Web 服务时，能够在 Web 浏览器上下载文件。
So I wrote the following code:
所以我写了下面的代码：
@app.route("/api/downloadlogfile/<path>")
def DownloadLogFile (path = None):
if path is None:
self.Error(400)
try:
with open(path, 'r') as f:
response = make_response(f.read())
response.headers["Content-Disposition"] = "attachment; filename=%s" % path.split("/")[2]
return response
except Exception as e:
self.log.exception(e)
self.Error(400)
But this code doesn't seem to work. Indeed I get an error that I didn't manage to fix:
但是这段代码似乎不起作用。事实上，我收到了一个我无法修复的错误：
Traceback (most recent call last):
File "C:\Python27\lib\site-packages\gevent\pywsgi.py", line 508, in handle_one_response
self.run_application()
File "C:\Python27\lib\site-packages\geventwebsocket\handler.py", line 88, in run_application
return super(WebSocketHandler, self).run_application()
File "C:\Python27\lib\site-packages\gevent\pywsgi.py", line 495, in run_application
self.process_result()
File "C:\Python27\lib\site-packages\gevent\pywsgi.py", line 484, in process_result
for data in self.result:
File "C:\Python27\lib\site-packages\werkzeug\wsgi.py", line 703, in __next__
return self._next()
File "C:\Python27\lib\site-packages\werkzeug\wrappers.py", line 81, in _iter_encoded
for item in iterable:
TypeError: 'Response' object is not iterable
I update my Flask and Werkzeug package to the last version but without success.
我将 Flask 和 Werkzeug 包更新到最新版本，但没有成功。
If anybody have an idea it would be great.
如果有人有想法，那就太好了。
Thanks in advance
提前致谢
回答by K DawG
The best way to solve this issue is to use the already predefined helper function send_file()in flask:
解决这个问题的最好方法是使用send_file()flask中已经预定义好的辅助函数：
@app.route("/api/downloadlogfile/<path>")
def DownloadLogFile (path = None):
if path is None:
self.Error(400)
try:
return send_file(path, as_attachment=True)
except Exception as e:
self.log.exception(e)
self.Error(400)
