C++ cin 按键事件
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C++ cin keypress event
提问by Lukas Salich
I believe this is a very simple question, but I can't find a simple answer to it. I have an infinite loop, e.g. while(1), for(;;), and I need to break from the loop on a keypress. What is the easiest way to do this?
我相信这是一个非常简单的问题，但我找不到一个简单的答案。我有一个无限循环，例如while(1), for(;;)，我需要在按键时中断循环。什么是最简单的方法来做到这一点？
P.S.: I can't use getch, cin.ignore, or cin.getbecause it stops the loop.
PS：我不能使用getch, cin.ignore, 或者cin.get因为它会停止循环。
回答by Bartek Banachewicz
Well, what you want is asynchronous input. All of the methods provided by cinwait for enter. You will have to use system-specific functions for that, or use a library that will do it for you.
好吧，你想要的是异步输入。cinwait for enter提供的所有方法。为此，您必须使用系统特定的函数，或者使用可以为您完成的库。
What you need to do is to not only process your logic in a while loop, but also listen from message pipe from your OS. If you want some more information about that one, please drop a comment.
您需要做的不仅是在 while 循环中处理您的逻辑，而且还要从您的操作系统的消息管道中进行监听。如果你想了解更多关于那个的信息，请发表评论。
EDIT: There's one other way, but I wouldn't recommend it as it can be non-portable I believe. The following code compiles and runs under VS2012RC.
编辑：还有另一种方式，但我不推荐它，因为我相信它可能是不可移植的。以下代码在VS2012RC下编译运行。
#include<iostream>
#include<conio.h>
using namespace std;
int main()
{
cout << "Enter a character";
getch();
}
回答by Software_Designer
Below is a Windows console code that uses kbhit()and has an infinite loop.
But if keyboard is hit, it breaks the loop and exits.
If you have <conio.h>, try this :
下面是使用kbhit()并具有无限循环的 Windows 控制台代码。但是如果键盘被击中，它会中断循环并退出。如果你有<conio.h>，试试这个：
#include <iostream>
#include <conio.h>
using namespace std;
int main()
{
while (1)
{
if (kbhit()) break;
}
return 0;
}
回答by Kerrek SB
There is no "keyboard" in C++. You only have an opaque input data stream which your terminal populates occasionally with its own keyboard input. This is almost always a buffered, editable line-wise input, so you have no way of knowing when any given key was pressed.
C++ 中没有“键盘”。您只有一个不透明的输入数据流，您的终端偶尔会使用自己的键盘输入填充该数据流。这几乎总是一个缓冲的、可编辑的逐行输入，因此您无法知道何时按下了任何给定的键。
You need a platform-specific method to communicate directly with your terminal on a lower level. One such library, fairly wide-spread and portable, is ncurses(a compatible Windows variant exists). Portable graphical application frameworks such as SDL and Allegro also provide raw keyboard handling.
您需要一种特定于平台的方法来直接与较低级别的终端进行通信。一个这样的库，相当广泛且可移植，是ncurses（存在兼容的 Windows 变体）。SDL 和 Allegro 等便携式图形应用程序框架也提供原始键盘处理。
回答by huseyin tugrul buyukisik
This checks if "left arrow" is being pressed or not:
这将检查“左箭头”是否被按下：
GetKeyState(VK_LEFT)
Also this does not wait for anything. Just checks some flags.
此外，这不会等待任何事情。只是检查一些标志。
Some other keys defined in winuser.h:
winuser.h 中定义的其他一些键：
#define VK_NUMPAD0 0x60
#define VK_NUMPAD1 0x61
#define VK_NUMPAD2 0x62
#define VK_NUMPAD3 0x63
#define VK_NUMPAD4 0x64
#define VK_NUMPAD5 0x65
#define VK_NUMPAD6 0x66
#define VK_NUMPAD7 0x67
#define VK_NUMPAD8 0x68
#define VK_NUMPAD9 0x69
#define VK_CLEAR 0x0C
#define VK_RETURN 0x0D
#define VK_SHIFT 0x10
#define VK_CONTROL 0x11
#define VK_MENU 0x12
#define VK_PAUSE 0x13
#define VK_CAPITAL 0x14
#define VK_KANA 0x15
#define VK_HANGEUL 0x15 /* old name - should be here for compatibility */
#define VK_HANGUL 0x15
#define VK_JUNJA 0x17
#define VK_FINAL 0x18
#define VK_HANJA 0x19
#define VK_KANJI 0x19
#define VK_ESCAPE 0x1B
#define VK_CONVERT 0x1C
#define VK_NONCONVERT 0x1D
#define VK_ACCEPT 0x1E
#define VK_MODECHANGE 0x1F
#define VK_SPACE 0x20
#define VK_PRIOR 0x21
#define VK_NEXT 0x22
#define VK_END 0x23
#define VK_HOME 0x24
#define VK_LEFT 0x25
#define VK_UP 0x26
#define VK_RIGHT 0x27
#define VK_DOWN 0x28
#define VK_SELECT 0x29
#define VK_PRINT 0x2A
#define VK_EXECUTE 0x2B
#define VK_SNAPSHOT 0x2C
#define VK_INSERT 0x2D
#define VK_DELETE 0x2E
#define VK_HELP 0x2F
winuser.h must be included in windows.h
winuser.h 必须包含在 windows.h 中
