Java MQJE001：完成代码“2”，原因“2538”
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MQJE001: Completion Code '2', Reason '2538'
提问by Bhaumik Shah
public class PtpReceiver {
公共类 PtpReceiver {
public static void main(String[] args) {
// TODO Auto-generated method stub
try {
MQEnvironment.hostname = "192.168.120.28:1415";
MQEnvironment.channel = "SFMS.TO.CBS";
MQEnvironment.properties.put(MQC.TRANSPORT_PROPERTY,
MQC.TRANSPORT_MQSERIES);
System.out.println("Q manager");
MQQueueManager qMgr = new MQQueueManager("GSCBBRQM");
System.out.println("Q manager11");
}
catch (MQException ex) {
System.out.println(ex.completionCode+ ex.reasonCode);
}
}
}
}
I got the error following:
我收到以下错误：
MQJE001: Completion Code '2', Reason '2538'.
MQJE001：完成代码“2”，原因“2538”。
Can any one help me for solve this error
谁能帮我解决这个错误
采纳答案by Roger
That is JMS code for doing a connection via for WMQ for JMS. Bhaumik is using WMQ for Java (non JMS).
这是用于通过 WMQ for JMS 进行连接的 JMS 代码。Bhaumik 使用 WMQ for Java（非 JMS）。
Bhaumik, you do not specify the port number in the hostname but rather as follows:
Bhaumik，您没有在主机名中指定端口号，而是如下：
public static void main(String[] args) {
try {
MQEnvironment.hostname = "192.168.120.28";
MQEnvironment.port = 1415;
MQEnvironment.channel = "SFMS.TO.CBS";
MQQueueManager qMgr = new MQQueueManager("GSCBBRQM");
}
catch (MQException ex) {
System.out.println("CC="+ex.completionCode + " : RC="+ ex.reasonCode);
}
}
回答by Aliti
I think it is necessary to define your connection mode like this:
我认为有必要像这样定义你的连接模式：
jmsFactory = JmsFactoryFactory.getInstance(WMQConstants.WMQ_PROVIDER);
jcf = jmsFactory.createConnectionFactory();
// Set the properties
jcf.setStringProperty(WMQConstants.WMQ_HOST_NAME, hostName);
jcf.setIntProperty(WMQConstants.WMQ_PORT, port);
jcf.setIntProperty(WMQConstants.WMQ_CONNECTION_MODE, WMQConstants.WMQ_CM_CLIENT);
jcf.setStringProperty(WMQConstants.WMQ_CHANNEL, channel);
connection = jcf.createConnection();
I hope it works. For more inormation see this.
我希望它有效。有关更多信息，请参阅此。
