您可以使用 Laravel 5 在不在数据库中创建条目的情况下填充 Eloquent 模型吗
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Can you populate an Eloquent model without creating an entry in the database using Laravel 5
提问by Styphon
When I'm adding or editing an entry to my database table websitesI load the instance of the website to be modified (or a blank one for creating a website). This works great, this is my controller:
当我向我的数据库表网站添加或编辑条目时，我加载要修改的网站实例（或用于创建网站的空白实例）。这很好用，这是我的控制器：
<?php namespace App\Http\Controllers\Admin;
use App\Http\Controllers\Controller;
use Illuminate\Support\Facades\Request;
use App\Models\User;
use App\Models\Status;
use App\Models\Website;
class WebsitesController extends Controller {
/**
* Show / Process the create website form to the user.
*
* @return Response
*/
public function create()
{
$statuses = Status::all();
$users = User::all();
$website = Website::find(0);
return view('admin/websites/create', [
'statuses' => $statuses,
'users' => $users,
'website' => $website
]);
}
public function update($id)
{
$statuses = Status::all();
$users = User::all();
$website = Website::findOrFail($id);
return view('admin/websites/update', [
'statuses' => $statuses,
'users' => $users,
'website' => $website
]);
}
}
The problem is when I submit the form and there is an error. The user is returned to the page and the errors displayed. I also pass the users input back so I can repopulate the form with what they entered. But how can I replace the values in website with the values from input if it's present without actually saving to the database? I've been playing around with this all day and not found a working solution.
问题是当我提交表单时出现错误。用户返回到页面并显示错误。我还将用户输入传回，以便我可以用他们输入的内容重新填充表单。但是，如果网站中的值存在而没有实际保存到数据库中，我该如何用输入中的值替换网站中的值？我整天都在玩这个，但没有找到可行的解决方案。
My create method is this:
我的创建方法是这样的：
public function postCreate(Request $request)
{
$v = Validator::make($request->all(), Website::rules());
if ($v->fails())
{
return redirect()->back()->withInput()->withErrors($v);
}
$website = Website::create($request->all());
return redirect()->action('Admin\HomeController@index')->with('messages', [['text' => 'Website created', 'class' => 'alert-success']]);
}
I'm passing the input back to the original form, but the form populates its values from the Website Eloquent model. **How can I get the input from $request->all()into $website?
我将输入传递回原始表单，但该表单从网站 Eloquent 模型填充其值。**如何从$request->all()into获取输入$website？
I've tried using fill(), but I just get Call to a member function fill() on nullwhen using it in the create function.
我试过使用fill()，但我只是Call to a member function fill() on null在 create 函数中使用它时才得到。
回答by Don't Panic
The createmethod attempts to insert a record to the database and returns an instance of the model if it is successful. If you use create()with invalid values, the insert will fail. I think this is why there is a nullinstead of an instance of the model, which causes your error:
该create方法尝试向数据库插入一条记录，如果成功则返回模型的一个实例。如果使用create()无效值，插入将失败。我认为这就是为什么有一个null而不是模型的实例，这会导致您的错误：
Call to a member function fill() on null
在 null 上调用成员函数 fill()
Instead of using create()You could create the website model without the database insert using
而不是使用create()您可以使用创建没有数据库插入的网站模型
$website = new Website;
$website->fill($request->all());
before you run the validation. If the validation passes, then you can insert to your database with $website->save();, otherwise, it will not try to save, but the model should be available for you to use in your form.
在运行验证之前。如果验证通过，那么您可以使用 插入到您的数据库中$website->save();，否则，它不会尝试保存，但模型应该可供您在表单中使用。
