如何在python中打印字典的键值对
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How do I print the key-value pairs of a dictionary in python
提问by oaklander114
I want to output my key value pairs from a python dictionary as such:
我想从 python 字典中输出我的键值对，如下所示：
key1 \t value1
key2 \t value2
I thought I could maybe do it like this:
我想我可以这样做：
for i in d:
print d.keys(i), d.values(i)
but obviously that's not how it goes as the keys()and values()don't take an argument.
但显然这不是它的方式keys()，values()也不要争论。
采纳答案by chepner
Your existing code just needs a little tweak. iisthe key, so you would just need to use it:
您现有的代码只需要一点点调整。i是关键，所以你只需要使用它：
for i in d:
print i, d[i]
You can also get an iterator that contains both keys and values. In Python 2, d.items()returns a list of (key, value) tuples, while d.iteritems()returns an iterator that provides the same:
您还可以获得包含键和值的迭代器。在 Python 2 中，d.items()返回一个 (key, value) 元组列表，同时d.iteritems()返回一个提供相同内容的迭代器：
for k, v in d.iteritems():
print k, v
In Python 3, d.items()returns the iterator; to get a list, you need to pass the iterator to list()yourself.
在 Python 3 中，d.items()返回迭代器；要获取列表，您需要将迭代器传递给list()自己。
for k, v in d.items():
print(k, v)
回答by Mauro Baraldi
for key, value in d.iteritems():
print key, '\t', value
回答by Patrick Beeson
Or, for Python 3:
或者，对于 Python 3：
for k,v in dict.items():
print(k, v)
回答by Irshad Bhat
>>> d={'a':1,'b':2,'c':3}
>>> for kv in d.items():
... print kv[0],'\t',kv[1]
...
a 1
c 3
b 2
回答by Hackaholic
A little intro to dictionary
字典的一点介绍
d={'a':'apple','b':'ball'}
d.keys() # displays all keys in list
['a','b']
d.values() # displays your values in list
['apple','ball']
d.items() # displays your pair tuple of key and value
[('a','apple'),('b','ball')
Print keys,values method one
打印键值方法一
for x in d.keys():
print x +" => " + d[x]
Another method
另一种方法
for key,value in d.items():
print key + " => " + value
You can get keys using iter
您可以使用 iter
>>> list(iter(d))
['a', 'b']
You can get value of key of dictionary using get(key, [value]):
您可以使用get(key, [value])以下方法获取字典键的值：
d.get('a')
'apple'
If key is not present in dictionary,when default value given, will return value.
如果字典中不存在键，则在给定默认值时，将返回值。
d.get('c', 'Cat')
'Cat'
回答by SuperNova
In addition to ways already mentioned.. can use 'viewitems', 'viewkeys', 'viewvalues'
除了已经提到的方法..可以使用'viewitems'、'viewkeys'、'viewvalues'
>>> d = {320: 1, 321: 0, 322: 3}
>>> list(d.viewitems())
[(320, 1), (321, 0), (322, 3)]
>>> list(d.viewkeys())
[320, 321, 322]
>>> list(d.viewvalues())
[1, 0, 3]
Or
或者
>>> list(d.iteritems())
[(320, 1), (321, 0), (322, 3)]
>>> list(d.iterkeys())
[320, 321, 322]
>>> list(d.itervalues())
[1, 0, 3]
or using itemgetter
或使用 itemgetter
>>> from operator import itemgetter
>>> map(itemgetter(0), dd.items()) #### for keys
['323', '332']
>>> map(itemgetter(1), dd.items()) #### for values
['3323', 232]
回答by goulon
You can access your keys and/or values by calling items()on your dictionary.
您可以通过在字典中调用items()来访问您的键和/或值。
for key, value in d.iteritems():
print(key, value)
回答by paolof89
If you want to sortthe output by dict key you can use the collectionpackage.
如果要按dict 键对输出进行排序，可以使用集合包。
import collections
for k, v in collections.OrderedDict(sorted(d.items())).items():
print(k, v)
It works on python 3
它适用于python 3
回答by Fouad Boukredine
A simple dictionary:
一个简单的字典：
x = {'X':"yes", 'Y':"no", 'Z':"ok"}
To print a specific (key, value) pair in Python 3 (pair at index 1 in this example):
要在 Python 3 中打印特定的 (key, value) 对（在本例中为索引 1 的对）：
for e in range(len(x)):
print(([x for x in x.keys()][e], [x for x in x.values()][e]))
Output:
输出：
('X', 'yes')
('Y', 'no')
('Z', 'ok')
Here is a one liner solution to print all pairs in a tuple:
这是在元组中打印所有对的单行解决方案：
print(tuple(([x for x in x.keys()][i], [x for x in x.values()][i]) for i in range(len(x))))
Output:
输出：
(('X', 'yes'), ('Y', 'no'), ('Z', 'ok'))
回答by Nara Begnini
The dictionary:
词典：
d={'key1':'value1','key2':'value2','key3':'value3'}
Another one line solution:
另一种单行解决方案：
print(*d.items(), sep='\n')
Output:
输出：
('key1', 'value1')
('key2', 'value2')
('key3', 'value3')
(but, since no one has suggested something like this before, I suspect it is not good practice)
（但是，由于之前没有人提出过类似的建议，我怀疑这不是一个好习惯）
