C# 数据源是无效类型。它必须是 IListSource、IEnumerable 或 IDataSource
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Data source is an invalid type. It must be either an IListSource, IEnumerable, or IDataSource
提问by user1566490
Data source is an invalid type. It must be either an IListSource, IEnumerable, or IDataSource. The error is displayed when I bind the grid view
数据源是无效类型。它必须是 IListSource、IEnumerable 或 IDataSource。绑定网格视图时显示错误
var list = dal.GetEmployeebyName(name);
GridViewEmployee.DataSource = list;
GridViewEmployee.DataBind();
i have the query
我有疑问
public EmployeeInfo GetEmployeebyName(String name)
{
using (var context = new HRMSEntities())
{
return context.EmployeeInfo.FirstOrDefault(e => e.FName == name);
}
}
回答by Yograj Gupta
You are returning a single object from GetEmployeebyName method and binding that to the GridViewEmployee, thats why it is giving error.
您从 GetEmployeebyName 方法返回单个对象并将其绑定到 GridViewEmployee，这就是它给出错误的原因。
You can change it like
你可以改变它像
var empInfo = dal.GetEmployeebyName(name);
var list = new List<EmployeeInfo>{empInfo};
//or you can do this
//var list = new List<EmployeeInfo>();
//list.Add(empInfo);
GridViewEmployee.DataSource = list;
GridViewEmployee.DataBind();
DataSource must be a type of collection as the exception is stating ( It must be either an IListSource, IEnumerable, or IDataSource)
DataSource 必须是一种集合类型，因为异常声明（它必须是 IListSource、IEnumerable 或 IDataSource）
回答by uk2k05
Could the above not be shortend to..
以上不可以简写为..
var empInfo = dal.GetEmployeebyName(name);
GridViewEmployee.DataSource = empInfo.ToList();
GridViewEmployee.DataBind();
回答by FunMatters
In my testing page I make us of the following piece of code to display a list of different objects or just a single object in the same gridview.
在我的测试页面中，我让我们使用以下代码段来显示不同对象的列表或在同一个 gridview 中仅显示单个对象。
var data = bl.getAirlines();
// If single object returned cast to List
// Note that could be already a list of 1 item though!
if (data.Count == 1)
{
var list = new List<object> { data };
GridView1.DataSource = list;
}
else
// Bind to list of items returned
GridView1.DataSource = data;
GridView1.DataBind();
Hope it helps! It works for me :)
希望能帮助到你！这个对我有用 ：）
