如何杀死nodejs中的子进程？
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How to kill childprocess in nodejs?
提问by Deepak Patil
Created a childprocess using shelljs
使用shelljs创建了一个子进程
!/usr/bin/env node
require('/usr/local/lib/node_modules/shelljs/global');
fs = require("fs");
var child=exec("sudo mongod &",{async:true,silent:true});
function on_exit(){
console.log('Process Exit');
child.kill("SIGINT");
process.exit(0)
}
process.on('SIGINT',on_exit);
process.on('exit',on_exit);
Child process is still running .. after kill the parent process
子进程仍在运行 .. 杀死父进程后
回答by Michael Tang
If you can use node's built in child_process.spawn, you're able to send a SIGINTsignal to the child process:
如果您可以使用节点的内置child_process.spawn，则可以向SIGINT子进程发送信号：
var proc = require('child_process').spawn('mongod');
proc.kill('SIGINT');
An upside to this is that the main process should hang around until all of the child processes have terminated.
这样做的好处是，主进程应该一直运行，直到所有子进程都终止。
