PHP REGEX：从 URL 获取域
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PHP REGEX: Get domain from URL
提问by Adam
What I want
我想要的是
I want to get from a URLthe domainpart so from http://example.com/-> example.com
我希望从获得URL的domain一部分，所以从http://example.com/- >example.com
Examples:
例子：
+----------------------------------------------+-----------------------+
| input | output |
+----------------------------------------------+-----------------------+
| http://www.stackoverflow.com/questions/ask | www.stackoverflow.com |
| http://validator.w3.org/check | validator.w3.org |
| http://www.google.com/?q=hello | www.google.com |
| http://google.de/?q=hello | google.de |
+----------------------------------------------+-----------------------+
I found some related questions in stackoverflowbut none of them was exactly what I was looking for.
我发现了一些相关的问题，stackoverflow但没有一个是我正在寻找的。
Thanks for any help!
谢谢你的帮助！
回答by cletus
There's no need to use a regex for this. PHP has an inbuilt function to do just this. Use parse_url():
没有必要为此使用正则表达式。PHP 有一个内置函数可以做到这一点。使用parse_url()：
$domain = parse_url($url, PHP_URL_HOST);
回答by Marcin ?urek
I use:
我用：
$domain = parse_url('http://' . str_replace(array('https://', 'http://'), '', $url), PHP_URL_HOST);
Because parse_urldoesn't return host key when schema is missing in $url.
因为parse_url当$url.
回答by turbod
$tmp = parse_url($url);
$url = $tmp['host']
回答by fnkr
This is like the regex from theraccoonbearbut with support for HTTPS domains.
这就像来自 theraccoonbear的正则表达式，但支持 HTTPS 域。
if (preg_match('/https?:\/\/([^\/]+)\//i', $target_string, $matches)) {
$domain = $matches[1];
}
回答by Josh K
Assumes that http://prefixes everything.
假设http://前缀为所有内容。
$tmp = explode("/", $url);
$domain = $tmp[2];
回答by T.Todua
Best way i think:
我认为的最佳方式：
preg_match('/(http(|s)):\/\/(.*?)\//si', 'http://www.example.com/page/?bla=123#!@#$%^&*()_+', $output);
// $output[0] ------------> https://www.example.com/
回答by Eugen Mihailescu
I think the following regexp might answers your question.
我认为以下正则表达式可能会回答您的问题。
This diagramexplains how it works, or rather why it works :-)
这张图解释了它是如何工作的，或者更确切地说它为什么工作:-)
$regexp = '/.*\/\/([^\/:]+).*/';
// www.stackoverflow.com
echo preg_replace($regexp, '', 'http://www.stackoverflow.com/questions/ask');
// google.de
echo preg_replace($regexp, '', 'http://google.de/?q=hello');
// it works for the other input tests too ;-)
回答by haydenmuhl
Here's my quick and dirty solution.
这是我快速而肮脏的解决方案。
http://([^/]+).*
http://([^/]+).*
I haven't tested it, but it should grab anything between the http://and the first slash.
我还没有测试过它，但它应该抓住http://第一个斜线和第一个斜线之间的任何东西。
回答by theraccoonbear
if (preg_match('/http:\/\/([^\/]+)\//i', $target_string, $matches)) {
$domain = $matches[1];
}
