ios 在 iPhone App 中如何检测设备的屏幕分辨率
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StackOverFlow
in iPhone App How to detect the screen resolution of the device
提问by ios
In iPhone App, while running the App on device How to detect the screen resolution of the device on which App is running?
在 iPhone 应用程序中，在设备上运行应用程序时如何检测运行应用程序的设备的屏幕分辨率？
回答by James Linnell
CGRect screenBounds = [[UIScreen mainScreen] bounds];
That will give you the entire screen's resolution in points, so it would most typically be 320x480 for iPhones. Even though the iPhone4 has a much larger screen size iOS still gives back 320x480 instead of 640x960. This is mostly because of older applications breaking.
这将为您提供整个屏幕的分辨率（以点为单位），因此对于 iPhone，它通常为 320x480。即使 iPhone4 有更大的屏幕尺寸，iOS 仍然返回 320x480 而不是 640x960。这主要是因为较旧的应用程序中断。
CGFloat screenScale = [[UIScreen mainScreen] scale];
This will give you the scale of the screen. For all devices that do not have Retina Displays this will return a 1.0f, while Retina Display devices will give a 2.0f and the iPhone 6 Plus (Retina HD) will give a 3.0f.
这将为您提供屏幕的比例。对于所有没有 Retina Displays 的设备，这将返回 1.0f，而 Retina Display 设备将返回 2.0f，而 iPhone 6 Plus (Retina HD) 将返回 3.0f。
Now if you want to get the pixel width & height of the iOS device screen you just need to do one simple thing.
现在，如果您想获得 iOS 设备屏幕的像素宽度和高度，您只需要做一件简单的事情。
CGSize screenSize = CGSizeMake(screenBounds.size.width * screenScale, screenBounds.size.height * screenScale);
By multiplying by the screen's scale you get the actual pixel resolution.
通过乘以屏幕的比例，您可以获得实际的像素分辨率。
A good read on the difference between points and pixels in iOS can be read here.
可以在此处阅读有关 iOS 中点和像素之间差异的良好读物。
EDIT:(Version for Swift)
编辑：（Swift 版本）
let screenBounds = UIScreen.main.bounds
let screenScale = UIScreen.main.scale
let screenSize = CGSize(width: screenBounds.size.width * screenScale, height: screenBounds.size.height * screenScale)
回答by Taimur Ajmal
UIScreen class lets you find screen resolution in Points and Pixels.
UIScreen 类可让您以点数和像素数查找屏幕分辨率。
Screen resolutions is measured in Points or Pixels. It should never be confused with screen size. A smaller screen size can have higher resolution.
屏幕分辨率以点或像素为单位。它永远不应该与屏幕尺寸混淆。较小的屏幕尺寸可以具有较高的分辨率。
UIScreen's 'bounds.width' return rectangular size in Points 
UIScreen 的“bounds.width”以点数返回矩形大小
UIScreen's 'nativeBounds.width' return rectangular size in Pixels.This value is detected as PPI ( Point per inch ). Shows the sharpness & clarity of the Image on a device.
UIScreen 的“nativeBounds.width”以像素为单位返回矩形大小。此值被检测为 PPI（每英寸点数）。显示设备上图像的锐度和清晰度。
You can use UIScreen class to detect all these values.
您可以使用 UIScreen 类来检测所有这些值。
Swift3
斯威夫特3
// Normal Screen Bounds - Detect Screen size in Points.
let width = UIScreen.main.bounds.width
let height = UIScreen.main.bounds.height
print("\n width:\(width) \n height:\(height)")
// Native Bounds - Detect Screen size in Pixels.
let nWidth = UIScreen.main.nativeBounds.width
let nHeight = UIScreen.main.nativeBounds.height
print("\n Native Width:\(nWidth) \n Native Height:\(nHeight)")
Console
安慰
width:736.0
height:414.0
Native Width:1080.0
Native Height:1920.0
Swift 2.x
斯威夫特 2.x
//Normal Bounds - Detect Screen size in Points.
let width = UIScreen.mainScreen.bounds.width
let height = UIScreen.mainScreen.bounds.height
// Native Bounds - Detect Screen size in Pixels.
let nWidth = UIScreen.mainScreen.nativeBounds.width
let nHeight = UIScreen.mainScreen.nativeBounds.height
ObjectiveC
目标C
// Normal Bounds - Detect Screen size in Points.
CGFloat *width = [UIScreen mainScreen].bounds.size.width;
CGFloat *height = [UIScreen mainScreen].bounds.size.height;
// Native Bounds - Detect Screen size in Pixels.
CGFloat *width = [UIScreen mainScreen].nativeBounds.size.width
CGFloat *height = [UIScreen mainScreen].nativeBounds.size.width
回答by ios_av
Use it in App Delegate: I am using storyboard
在 App Delegate 中使用它：我正在使用故事板
- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions{
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;
//----------------HERE WE SETUP FOR IPHONE 4/4s/iPod----------------------
if(iOSDeviceScreenSize.height == 480){
UIStoryboard *iPhone35Storyboard = [UIStoryboard storyboardWithName:@"iPhone" bundle:nil];
// Instantiate the initial view controller object from the storyboard
UIViewController *initialViewController = [iPhone35Storyboard instantiateInitialViewController];
// Instantiate a UIWindow object and initialize it with the screen size of the iOS device
self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
// Set the initial view controller to be the root view controller of the window object
self.window.rootViewController = initialViewController;
// Set the window object to be the key window and show it
[self.window makeKeyAndVisible];
iphone=@"4";
NSLog(@"iPhone 4: %f", iOSDeviceScreenSize.height);
}
//----------------HERE WE SETUP FOR IPHONE 5----------------------
if(iOSDeviceScreenSize.height == 568){
// Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone4
UIStoryboard *iPhone4Storyboard = [UIStoryboard storyboardWithName:@"iPhone5" bundle:nil];
// Instantiate the initial view controller object from the storyboard
UIViewController *initialViewController = [iPhone4Storyboard instantiateInitialViewController];
// Instantiate a UIWindow object and initialize it with the screen size of the iOS device
self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
// Set the initial view controller to be the root view controller of the window object
self.window.rootViewController = initialViewController;
// Set the window object to be the key window and show it
[self.window makeKeyAndVisible];
NSLog(@"iPhone 5: %f", iOSDeviceScreenSize.height);
iphone=@"5";
}
} else if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {
// NSLog(@"wqweqe");
storyboard = [UIStoryboard storyboardWithName:@"iPad" bundle:nil];
}
return YES;
}
回答by boog
For iOS 8 we can just use this [UIScreen mainScreen].nativeBounds, like that:
对于 iOS 8，我们可以使用 this [UIScreen mainScreen].nativeBounds，就像这样：
- (NSInteger)resolutionX
{
return CGRectGetWidth([UIScreen mainScreen].nativeBounds);
}
- (NSInteger)resolutionY
{
return CGRectGetHeight([UIScreen mainScreen].nativeBounds);
}
回答by Constantin
See the UIScreen Reference: http://developer.apple.com/library/ios/#documentation/uikit/reference/UIScreen_Class/Reference/UIScreen.html
请参阅 UIScreen 参考：http: //developer.apple.com/library/ios/#documentation/uikit/reference/UIScreen_Class/Reference/UIScreen.html
if([[UIScreen mainScreen] respondsToSelector:NSSelectorFromString(@"scale")])
{
if ([[UIScreen mainScreen] scale] < 1.1)
NSLog(@"Standard Resolution Device");
if ([[UIScreen mainScreen] scale] > 1.9)
NSLog(@"High Resolution Device");
}
回答by Shahzaib Maqbool
Use this code it will help for getting any type of device's screen resolution
使用此代码将有助于获得任何类型的设备的屏幕分辨率
[[UIScreen mainScreen] bounds].size.height
[[UIScreen mainScreen] bounds].size.width
