windows 从 SVN 命令行中提取文件的修订号
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Extracting the Revision number of a file from the SVN Command line
提问by this-Me
Hello Basically i need to extract the version info from the XML I thought of puttin the entire result to a XML file and then parse it to get the revision information.
你好 基本上我需要从 XML 中提取版本信息，我想将整个结果放入一个 XML 文件，然后解析它以获取修订信息。
i tried to output the svn info to a xml file by specifying
我试图通过指定将 svn 信息输出到 xml 文件
$ svn info C:\Projects\Foo.xml --xml C:\Projects\FileInfo.xml
Im getting errors if i try to save
如果我尝试保存，我会收到错误
$ svn info --xml C:\Projects\Foo.xml
<?xml version="1.0"?>
<info>
<entry
kind="dir"
path="."
revision="1">
<url>https://rbins.com/trunk/Projects/Foo.xml</url>
<repository>
<root>https://rbins.com/trunk/Projects/</root>
<uuid>5e7d134a-54fb-0310-bd04-b611643e5c25</uuid>
</repository>
<wc-info>
<schedule>normal</schedule>
<depth>infinity</depth>
</wc-info>
<commit
revision="240">
<author>sally</author>
<date>2003-01-15T23:35:12.847647Z</date>
</commit>
</entry>
</info>
i do not receive error if i run
如果我运行，我不会收到错误
$ svn info C:\Projects\Foo.xml --xml
$ svn 信息 C:\Projects\Foo.xml --xml
Help me where am i going wrong also suggest me if theres any alternative available to extract the revision number of the working copy
帮助我我哪里出错了还建议我是否有任何替代方法可以提取工作副本的修订号
Thanks in advance
提前致谢
回答by Jason S
回答by Antonio Pérez
You need to redirectsvn info's output to the file, the --xmloption takes no parameter:
您需要将svn info的输出重定向到文件，该--xml选项不带参数：
svn info C:\Projects\Foo.xml --xml >C:\Projects\FileInfo.xml
svn 信息 C:\Projects\Foo.xml --xml >C:\Projects\FileInfo.xml
