如何在python中减去日期时间/时间戳
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How to subtract datetimes / timestamps in python
提问by Jeff F
Seems like this should be so simple but for the life of me, I can't find the answer. I pull two datetimes/timestamps from the database:
看起来这应该很简单，但对于我的生活，我找不到答案。我从数据库中提取两个日期时间/时间戳：
2015-08-10 19:33:27.653
2015-08-10 19:31:28.209
How do I subtract the first from the second, preferably the result being in milliseconds? And yes, I have the date in there, too, because I need it to work at around midnight, as well.
如何从第二个中减去第一个，最好以毫秒为单位的结果？是的，我也有日期，因为我也需要它在午夜左右工作。
采纳答案by Yaroslav Admin
Parse your strings as datetime.datetimeobjects and subtract them:
将您的字符串解析为datetime.datetime对象并减去它们：
from datetime import datetime
d1 = datetime.strptime("2015-08-10 19:33:27.653", "%Y-%m-%d %H:%M:%S.%f")
d2 = datetime.strptime("2015-08-10 19:31:28.209", "%Y-%m-%d %H:%M:%S.%f")
print(d1 - d2)
Gives me:
给我：
0:01:59.444000
Also check out timedeltadocumentation for all possible operations.
还要查看timedelta所有可能操作的文档。
回答by Chris Montanaro
you can do subtraction on 2 datetime objects to get the difference
您可以对 2 个日期时间对象进行减法运算以获得差异
>>> import time
>>> import datetime
>>>
>>> earlier = datetime.datetime.now()
>>> time.sleep(10)
>>> now = datetime.datetime.now()
>>>
>>> diff = now - earlier
>>> diff.seconds
10
convert your strings to datetime objects with time.strptime
使用time.strptime将字符串转换为日期时间对象
datetime.strptime("2015-08-10 19:33:27.653", "%Y-%m-%d %H:%M:%S.%f")
回答by cameron-f
For python 3.4, first you'd need to convert the strings representing times into datetime objects, then the datetimemodule has helpful tools work with dates and times.
对于python 3.4，首先您需要将表示时间的字符串转换为日期时间对象，然后日期时间模块具有处理日期和时间的有用工具。
from datetime import datetime
def to_datetime_object(date_string, date_format):
s = datetime.strptime(date_string, date_format)
return s
time_1 = '2015-08-10 19:33:27'
time_2 = '2015-08-10 19:31:28'
date_format = "%Y-%m-%d %H:%M:%S"
time_1_datetime_object = to_datetime_object(time_1, date_format)
time_2_datetime_object = to_datetime_object(time_2, date_format)
diff_time = time_1_datetime_object - time_2_datetime_object
回答by Bobby Zandavi
timedelta.secondsdoes not represent the total number of seconds in the timedelta, but the total number of seconds modulus 60.
timedelta.seconds不代表timedelta中的总秒数，而是模数60的总秒数。
Call the function timedelta.total_seconds()instead of accessing the timedelta.secondsproperty.
调用函数timedelta.total_seconds()而不是访问timedelta.seconds属性。
