javascript 更改嵌套 JSON 结构中的键名
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Change key name in nested JSON structure
提问by user1842231
I have a JSON data structure as shown below:
我有一个 JSON 数据结构，如下所示：
{
"name": "World",
"children": [
{ "name": "US",
"children": [
{ "name": "CA" },
{ "name": "NJ" }
]
},
{ "name": "INDIA",
"children": [
{ "name": "OR" },
{ "name": "TN" },
{ "name": "AP" }
]
}
]
};
I need to change the key names from "name" & "children" to say "key" & "value". Any suggestion on how to do that for each key name in this nested structure?
我需要将键名从“名称”和“孩子”更改为“键”和“值”。关于如何针对此嵌套结构中的每个键名执行此操作的任何建议？
回答by I Hate Lazy
I don't know why you have a semicolon at the end of your JSON markup (assuming that's what you've represented in the question), but if that's removed, then you can use a reviver functionto make modifications while parsing the data.
我不知道为什么你的 JSON 标记末尾有一个分号（假设这就是你在问题中所表示的），但如果它被删除，那么你可以使用reviver 函数在解析数据时进行修改。
var parsed = JSON.parse(myJSONData, function(k, v) {
if (k === "name")
this.key = v;
else if (k === "children")
this.value = v;
else
return v;
});
回答by Denys Séguret
You could use a function like this :
你可以使用这样的函数：
function clonerename(source) {
if (Object.prototype.toString.call(source) === '[object Array]') {
var clone = [];
for (var i=0; i<source.length; i++) {
clone[i] = goclone(source[i]);
}
return clone;
} else if (typeof(source)=="object") {
var clone = {};
for (var prop in source) {
if (source.hasOwnProperty(prop)) {
var newPropName = prop;
if (prop=='name') newPropName='key';
else if (prop=='children') newPropName='value';
clone[newPropName] = clonerename(source[prop]);
}
}
return clone;
} else {
return source;
}
}
var B = clonerename(A);
Note that what you have isn't a JSON data structure (this doesn't exist as JSON is a data-exchange format) but probably an object you got from a JSON string.
请注意，您拥有的不是 JSON 数据结构（这不存在，因为JSON 是一种数据交换格式），而可能是您从 JSON 字符串中获得的对象。
回答by loganfsmyth
Try this:
试试这个：
function convert(data){
return {
key: data.name,
value: data.children.map(convert);
};
}
Or if you need to support older browsers without map:
或者，如果您需要支持没有地图的旧浏览器：
function convert(data){
var children = [];
for (var i = 0, len = data.children.length; i < len; i++){
children.push(convert(data.children[i]));
}
return {
key: data.name,
value: children
};
}
