vb.net 如何将答案转换为两位小数

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时间:2020-09-09 16:54:21  来源:igfitidea点击:

How to convert answer into two decimal point

vb.net

提问by Husna5207

This is my code and I want the output which is txtA.Textand txtB.Textto be in two decimal places.

这是我的代码,我希望输出是txtA.TexttxtB.Text小数点后两位。

Public Class Form1
    Private Sub btncalc_Click(ByVal sender As System.Object,
                              ByVal e As System.EventArgs) Handles btncalc.Click
      txtA.Text = Val(txtD.Text) / Val(txtC.Text) * Val(txtF.Text) / Val(txtE.Text)
      txtB.Text = Val(txtA.Text) * 1000 / Val(txtG.Text)
    End Sub
End Class

回答by fnostro

For formatting options, see this

有关格式选项,请参阅

Dim v1 as Double = Val(txtD.Text) / Val(txtC.Text) *
                   Val(txtF.Text) / Val(txtE.Text)
txtA.text = v1.ToString("N2");

回答by Andrea

Try using the Formatfunction:

尝试使用该Format功能:

Private Sub btncalc_Click(ByVal sender As System.Object,
                          ByVal e As System.EventArgs) Handles btncalc.Click
  txtA.Text = Format(Val(txtD.Text) / Val(txtC.Text) * 
                     Val(txtF.Text) / Val(txtE.Text), "0.00")
  txtB.Text = Format(Val(txtA.Text) * 1000 / Val(txtG.Text), "0.00")
End Sub

回答by Douglas Barbin

If you have a Decimal or similar numeric type, you can use:

如果您有 Decimal 或类似的数字类型,则可以使用:

Math.Round(myNumber, 2)

EDIT: So, in your case, it would be:

编辑:所以,在你的情况下,它将是:

Public Class Form1
  Private Sub btncalc_Click(ByVal sender As System.Object,
                            ByVal e As System.EventArgs) Handles btncalc.Click
    txtA.Text = Math.Round((Val(txtD.Text) / Val(txtC.Text) * Val(txtF.Text) / Val(txtE.Text)), 2)
    txtB.Text = Math.Round((Val(txtA.Text) * 1000 / Val(txtG.Text)), 2)
  End Sub
End Class

回答by vicsar

Call me lazy but:

叫我懒惰但是:

 lblTellBMI.Text = "Your BMI is: " & Math.Round(sngBMI, 2)

I.e.: Label lblTellBMIwill display Your BMI is:and then append the value from a Singletype variable (sngBMI) as 2 decimal points, simply by using the Math.Roundmethod.

即:标签lblTellBMI将显示您的 BMI 是:然后将来自单一类型变量 ( sngBMI)的值附加为 2 个小数点,只需使用Math.Round方法即可。

The Math.Roundmethod rounds a value to the nearest integer or to the specified number of fractional digits.

Math.Round方法舍入的值到最接近的整数或小数位指定数目。

Source: https://msdn.microsoft.com/en-us/library/system.math.round(v=vs.110).aspx

来源:https: //msdn.microsoft.com/en-us/library/system.math.round(v=vs.110).aspx

回答by SEFL

Ran into this problem today and I wrote a function for it. In my particular case, I needed to make sure all values were at least 0 (hence the "LT0" name) and were rounded to two decimal places.

今天遇到这个问题,我为它写了一个函数。在我的特殊情况下,我需要确保所有值至少为 0(因此是“LT0”名称)并四舍五入到小数点后两位。

        Private Function LT0(ByVal Input As Decimal, Optional ByVal Precision As Int16 = 2) As Decimal

            ' returns 0 for all values less than 0, the decimal rounded to (Precision) decimal places otherwise.
            If Input < 0 Then Input = 0
            if Precision < 0 then Precision = 0 ' just in case someone does something stupid.
            Return Decimal.Round(Input, Precision) ' this is the line everyone's probably looking for.

        End Function

回答by manuel

If you just want to print a decimal number with 2 digits after decimal point in specific format no matter of locals use something like this

如果您只想以特定格式打印小数点后 2 位的十进制数,无论本地人如何,请使用这样的方法

dim d as double = 1.23456789
dim s as string = d.Tostring("0.##", New System.Globalization.CultureInfo("en-US"))