类型错误：只能将列表（不是“int”）连接到 python 中
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TypeError: can only concatenate list (not "int") to list in python
提问by Tung Pham
I tried to run this code, but it showed an error:
我尝试运行此代码，但显示错误：
def shoot(aliens):
s=[0]*1000
s[0]=0
s[1]=1
num=len(aliens)
b=[[0 for m in range(1000)] for n in range(1000)]
for j in xrange(2,num):
for i in xrange(0,j):
b[j][i]=s[i]+min(int(aliens[j]),f[j-i]) ##Error here
s[j]=max(b)
and the error:
和错误：
Traceback (most recent call last):
File "module1.py", line 67, in <module>
print shoot(line)
File "module1.py", line 26, in shoot
b[j][i]=s[i]+min(int(aliens[j]),f[j-i])
TypeError: can only concatenate list (not "int") to list
please help!
请帮忙！
Edit: added more code. s, aliens and f are other arrays. I tried to save the result to the 2 dimentional array, but it showed that error.
编辑：添加了更多代码。s、aliens 和 f 是其他数组。我试图将结果保存到二维数组中，但它显示了该错误。
回答by nicolas.leblanc
try:
尝试：
b=[[0 for m in range(1000)] for n in range(1000)]
for j in xrange(2,num):
for i in xrange(0,j):
b[j][i] = s[j][i] + min(int(aliens[j]),f[j-i])
It seems to me likes is a 2D list (list of a list), and thus, you can't perform the operation.
在我看来，喜欢的是一个 2D 列表（列表的列表），因此，您无法执行该操作。
s[j] + min(int(aliens[j]),f[j-i])
回答by user2357112 supports Monica
s[j] = max(b)
doesn't treat bas a 2-d array of integers and pick the biggest one. bis a list of lists. max(b)compares the lists and returns the one that compares highest. (List comparison is done by comparing the elements lexicographically.)
不会将其b视为二维整数数组并选择最大的一个。b是一个列表列表。max(b)比较列表并返回比较最高的列表。（列表比较是通过按字典顺序比较元素来完成的。）
You want
你要
s[j] = max(max(sublist) for sublist in b)
回答by caytekin
I got the same error with the following python code:
我使用以下 python 代码遇到了同样的错误：
retList = []
for anItem in aList:
if anItem % 2 == 0:
retList = retList + anItem
return retList
when I changed the "+" which I used for concatenation to an append statement:
当我将用于连接的“+”更改为 append 语句时：
retList = []
for anItem in aList:
if anItem % 2 == 0:
retList.append(anItem)
return retList
it worked fine.
它工作正常。
