python Python中是否有一个函数可以在不忽略空格的情况下拆分字符串？
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Is there a function in Python to split a string without ignoring the spaces?
提问by gath
Is there a function in Python to split a string without ignoring the spaces in the resulting list?
Python 中是否有一个函数可以在不忽略结果列表中的空格的情况下拆分字符串？
E.g:
例如：
s="This is the string I want to split".split()
gives me
给我
>>> s
['This', 'is', 'the', 'string', 'I', 'want', 'to', 'split']
I want something like
我想要类似的东西
['This',' ','is',' ', 'the',' ','string', ' ', .....]
回答by Greg Hewgill
>>> import re
>>> re.split(r"(\s+)", "This is the string I want to split")
['This', ' ', 'is', ' ', 'the', ' ', 'string', ' ', 'I', ' ', 'want', ' ', 'to', ' ', 'split']
Using the capturing parentheses in re.split() causes the function to return the separators as well.
在 re.split() 中使用捕获括号会导致函数也返回分隔符。
回答by Mez
I don't think there is a function in the standard library that does that by itself, but "partition" comes close
我认为标准库中没有一个函数可以自行完成，但是“分区”很接近
The best way is probably to use regular expressions (which is how I'd do this in any language!)
最好的方法可能是使用正则表达式（这就是我在任何语言中都会这样做的方式！）
import re
print re.split(r"(\s+)", "Your string here")
回答by Foon
Silly answer just for the heck of it:
愚蠢的回答只是为了它：
mystring.replace(" ","! !").split("!")
回答by rossp
The hard part with what you're trying to do is that you aren't giving it a character to split on. split() explodes a string on the character you provide to it, and removes that character.
你想要做的事情的难点在于你没有给它一个可以分裂的角色。split() 在您提供给它的字符上分解一个字符串，并删除该字符。
Perhaps this may help:
也许这可能会有所帮助：
s = "String to split"
mylist = []
for item in s.split():
mylist.append(item)
mylist.append(' ')
mylist = mylist[:-1]
Messy, but it'll do the trick for you...
凌乱，但它会为你做的伎俩......
