Java Hibernate 5 中弃用的 createCriteria 方法

Deprecated createCriteria method in Hibernate 5

提问by faoxis

This calling is deprecated:

此调用已弃用：

session.createCriteria(Bus.class).list();

In source files I can see this:

在源文件中，我可以看到：

/** @deprecated */
@Deprecated
Criteria createCriteria(Class var1);

/** @deprecated */
@Deprecated
Criteria createCriteria(Class var1, String var2);

/** @deprecated */
@Deprecated
Criteria createCriteria(String var1);

/** @deprecated */
@Deprecated
Criteria createCriteria(String var1, String var2);

But I can't understand which method I have to use instead of createCriteria.

但我无法理解我必须使用哪种方法而不是createCriteria.

采纳答案by DimaSan

You can use the following interfaces instead in Hibernate 5.2 +:

您可以在 Hibernate 5.2 + 中使用以下接口：

javax.persistence.criteria.CriteriaBuilder
javax.persistence.criteria.CriteriaQuery

// Create CriteriaBuilder
CriteriaBuilder builder = session.getCriteriaBuilder();

// Create CriteriaQuery
CriteriaQuery<YourClass> criteria = builder.createQuery(YourClass.class);

回答by pleft

from the API documentation:

来自 API 文档：

@Deprecated Criteria createCriteria(Class persistentClass) Deprecated. (since 5.2) for Session, use the JPA Criteria Create Criteria instance for the given class (entity or subclasses/implementors). Parameters: persistentClass - The class, which is an entity, or has entity subclasses/implementors Returns: The criteria instance for manipulation and execution

@Deprecated Criteria createCriteria(Class persistentClass) 已弃用。（自 5.2 起）对于 Session，使用 JPA Criteria Create Criteria 实例为给定类（实体或子类/实现器）。参数：persistentClass - 类，它是一个实体，或具有实体子类/实现器返回：操作和执行的标准实例

So it briefly says to...

所以它简要地说...

use the JPA Criteria Create Criteria

使用 JPA 标准创建标准

回答by STEEL

Adding Answer as of March 2018.

截至 2018 年 3 月添加答案。

Dependencies:

依赖项：

import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.boot.MetadataSources;
import org.hibernate.boot.registry.StandardServiceRegistryBuilder;
import org.hibernate.service.ServiceRegistry;

import javax.persistence.criteria.CriteriaQuery;
import java.util.List;



public static List<Contact> fecthAllContacts() {
        Session session = sessionFactory.openSession();

        // create Criteria
        CriteriaQuery<Contact> criteriaQuery = session.getCriteriaBuilder().createQuery(Contact.class);
        criteriaQuery.from(Contact.class);

        List<Contact> contacts = session.createQuery(criteriaQuery).getResultList();
        session.close();

        return contacts;
    }

while the sessionFactoryis:

而sessionFactory为：

public static SessionFactory buildSessionFactory() {
        final ServiceRegistry registry = new StandardServiceRegistryBuilder().configure().build();
        return new MetadataSources(registry).buildMetadata().buildSessionFactory();
    }

回答by justMe

I had the following method, changed the object names for security reasons:

我有以下方法，出于安全原因更改了对象名称：

public List<MyObject> listAllForIds(List<Long> ids) {
    Criteria criteria = getSessionFactory().getCurrentSession().createCriteria(MyObject.class)
            .createAlias("joinObject", "joinObject")
            .add(Restrictions.not(Restrictions.like("name", "string1", MatchMode.END)))
            .add(Restrictions.not(Restrictions.like("name", "string2", MatchMode.END)))
            .add(Restrictions.in("joinObject.id", ids));

    return criteria.list();
}

Changing that to use:

将其更改为使用：

javax.persistence.criteria.CriteriaBuilder
javax.persistence.criteria.CriteriaQuery

The query look like the following:

查询如下所示：

public List<MyObject> listAllForIds(List<Long> ids) {

    CriteriaBuilder builder = getSessionFactory().getCurrentSession().getCriteriaBuilder();
    CriteriaQuery<MyObject> criteria = builder.createQuery(MyObject.class);
    Root<MyObject> myObjectRoot = criteria.from(MyObject.class);
    Join<MyObject, JoinObject> joinObject = myObjectRoot.join("joinObject");

    Predicate likeRestriction = builder.and(
            builder.notLike( myObjectRoot.get("name"), "%string1"),
            builder.notLike( myObjectRoot.get("name"), "%string2")
    );

    criteria.select(myObjectRoot).where(joinObject.get("id").in(ids), likeRestriction);

    TypedQuery<MyObject> query = getSessionFactory().getCurrentSession().createQuery(criteria);

    return query.getResultList();
}

Hope it helps someone else, please feel free to suggest any chanages to improve the code.

希望它可以帮助其他人，请随时提出任何改进代码的建议。