Javascript -- 只获取正则表达式匹配的可变部分
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Javascript -- get only the variable part of a regex match
提问by morgancodes
given:
给出：
var regexp = new RegExp("<~~include(.*?)~~>", "g");
What's the easist way in javascript to assign a variable to whatever's matched by .*?
javascript 中将变量分配给.* 匹配的任何内容的最简单方法是什么？
I can do this, but it's a little ugly:
我可以做到这一点，但它有点难看：
myString.match(regexp).replace("<~~include", "").replace("~~>", "");
采纳答案by eldarerathis
Javascript should return an array object on a regex match, where the zero index of the array is the whole string that was matched and the following indexes are the capture groups. In your case something like:
Javascript 应该在正则表达式匹配时返回一个数组对象，其中数组的零索引是匹配的整个字符串，以下索引是捕获组。在你的情况下是这样的：
var myVar = regexp.exec(myString)[1];
var myVar = regexp.exec(myString)[1];
should assign the value of the (.*?)capture group to myVar.
应该将(.*?)捕获组的值分配给myVar.
回答by Matt Ball
(Quotes from MDC)
（来自MDC 的报价）
Including parentheses in a regular expression pattern causes the corresponding submatch to be remembered. For example,
/a(b)c/matches the characters'abc'and remembers'b'.
在正则表达式模式中包含括号会导致记住相应的子匹配。例如，
/a(b)c/匹配字符'abc'并记住'b'。
Since .*?is the first (and only) remembered match, use $1in your replacement string:
由于.*?是第一个（也是唯一一个）记住的匹配项，请$1在替换字符串中使用：
var foo = myString.replace(regexp, '');
Edit:As per your comment, you can also (perhaps with clearer intention) do this:
编辑：根据您的评论，您也可以（也许有更明确的意图）这样做：
var foo = regexp.exec(myString)[1];
回答by Skyler
You can use lookahead for part of this regular expression. See here:
您可以对这个正则表达式的一部分使用前瞻。看这里：
Regular expression for extracting a number
and/or here:
和/或在这里：
