php 从 Zend 框架中的视图获取基本路径
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Getting basepath from view in zend framework
提问by Mads Mob?k
Case: you're developing a site with Zend Framework and need relative links to the folder the webapp is deployed in. I.e. mysite.com/folderonline and localhost:8080under development.
案例：您正在使用 Zend Framework 开发一个站点，并且需要指向部署 webapp 的文件夹的相关链接。即mysite.com/folder在线和localhost:8080正在开发中。
The following works nice in controllers regardless of deployed location:
无论部署位置如何，以下在控制器中都很好用：
$this->_helper->redirector->gotoSimple($action, $controller, $module, $params);
And the following inside a viewscript, ie. index.phtml:
下面是一个视图脚本，即。索引.phtml：
<a href="<?php echo $this->url(array('controller'=>'index', 'action' => 'index'), null, true); ?>">
But how do I get the correct basepath when linking to images or stylesheets? (in a layout.phtml file, for example):
但是在链接到图像或样式表时如何获得正确的基本路径？（例如在 layout.phtml 文件中）：
<img src='<?php echo WHAT_TO_TYPE_HERE; ?>images/logo.png' />
and
和
$this->headLink()->appendStylesheet( WHAT_TO_TYPE_HERE . 'css/default.css');
WHAT_TO_TYPE_HEREshould be replaced with something that gives
WHAT_TO_TYPE_HERE应该用可以提供的东西代替
<img src="/folder/images/logo.png />` on mysite.com and `<img src="/images/logo.png />
on localhost
在本地主机上
回答by Akeem
You can get the base url from the Front Controller Zend_Controller_Front::getInstance()->getBaseUrl();. I wrap that in a view helper
您可以从 Front Controller 获取基本 url Zend_Controller_Front::getInstance()->getBaseUrl();。我把它包装在一个视图助手中
class My_View_Helper_BaseUrl
{
/**
* Get base url
*
* @return string
*/
public function baseUrl()
{
return rtrim(Zend_Controller_Front::getInstance()->getBaseUrl(),'/');
}
}
So in the html markup you have something like <img src="<?php echo $this->baseUrl();?>/images/logo.png"/>The trailing slash is stripped out in the helper so that when the application isn't run in a sub folder (baseUrl is blank in that case) the path will still work.
因此，在 html 标记中，您可以<img src="<?php echo $this->baseUrl();?>/images/logo.png"/>在帮助程序中删除尾部斜杠之类的内容，以便当应用程序不在子文件夹中运行时（在这种情况下 baseUrl 为空），路径仍然有效。
回答by puppybits
In case anyone wants to know the best way and doesn't want to waste 2 hours searching Zend/Google. There is a view helper to do that.
如果有人想知道最好的方法并且不想浪费 2 小时搜索 Zend/Google。有一个视图助手可以做到这一点。
$this->view->serverUrl();
回答by irfan khan
If do you want to host name in your layoutfile so print this and get your HOSTname:
如果您想在layout文件中包含主机名，请打印此文件并获取您的HOST姓名：
echo $this->serverUrl().$this->baseUrl()
回答by irfan khan
This is my baseUrlhelper:
这是我的baseUrl助手：
class Zend_View_Helper_BaseUrl extends Zend_View_Helper_Abstract {
public function baseUrl() {
$protocol = isset($_SERVER['HTTPS']) ? 'https' : 'http';
$server = $_SERVER['HTTP_HOST'];
$port = $_SERVER['SERVER_PORT'] != 80 ? ":{$_SERVER['SERVER_PORT']}" : '';
$path = rtrim(dirname($_SERVER['SCRIPT_NAME']), '/\') . '/';
return "$protocol://$server$port$path";
}
}
回答by RoboTamer
<?php
/**
*
* @package TaMeR Library
* @copyright (C) 2010 Dennis T Kaplan
* @license GPL {@link http://www.gnu.org/licenses/gpl.html}
*
* @author Dennis T Kaplan
*/
/** @see Zend_View_Helper_Abstract */
require_once 'Zend/View/Helper/Abstract.php';
class TaMeR_View_Helper_BaseUrl extends Zend_View_Helper_Abstract {
/**
* Returns site's base url, or file with base url prepended
*
* $file is appended to the base url for simplicity
*
* @param string|null $file
* @return string
*/
public function baseUrl($file = NULL) {
$baseUrl = $domain = $subdomain = $protocol = $host = $port = NULL;
$host = array_reverse(explode('.', $_SERVER['HTTP_HOST']));
$domain = $host[1].'.'.$host[0];
$subdomain = (isset($host[2]) ? $host[2] : 'www');
if(getenv("HTTPS") == 'on') {
$protocol = 'https';
$port = $_SERVER['SERVER_PORT'] != 443 ? ':'.$_SERVER['SERVER_PORT'] : '';
}else{
$protocol = 'http';
$port = $_SERVER['SERVER_PORT'] != 80 ? ':'.$_SERVER['SERVER_PORT'] : '';
}
// Remove trailing slashes
if(NULL !== $file) {
$file = '/' . ltrim($file, '/\');
}else{
$file = rtrim(dirname($_SERVER['SCRIPT_NAME']), '/') . '/';
}
$baseUrl = $protocol.'://'.$subdomain.'.'.$domain.$port.$file;
return $baseUrl;
}
}
回答by Strategist
This worked for me:
这对我有用：
echo $this->serverUrl() . $this->url()
回声 $this->serverUrl() 。$this->url()
