ios 如何在Objective-C中四舍五入为2位小数
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原文地址: http://stackoverflow.com/questions/15429221/
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How to round decimal for 2 decimal places in Objective-C
提问by Takuya Takahashi
Let me know how to round decimal for 2 decimal places in Objective-C.
让我知道如何在 Objective-C 中将小数点四舍五入到小数点后两位。
I would like to do like this. (all of numbers following sentence is float value)
我想这样做。（句子后面的所有数字都是浮点值）
? round
? 圆形的
10.118 => 10.12
10.118 => 10.12
10.114 => 10.11
10.114 => 10.11
? ceil
? 细胞
10.118 => 10.12
10.118 => 10.12
? floor
? 地面
10.114 => 10.11
10.114 => 10.11
Thanks for checking my question.
感谢您检查我的问题。
回答by
If you actually need the number to be rounded, and not just when presenting it:
如果您确实需要对数字进行四舍五入，而不仅仅是在呈现时：
float roundToN(float num, int decimals)
{
int tenpow = 1;
for (; decimals; tenpow *= 10, decimals--);
return round(tenpow * num) / tenpow;
}
Or always to two decimal places:
或始终保留两位小数：
float roundToTwo(float num)
{
return round(100 * num) / 100;
}
回答by Suhaiyl
You can use the below code to format it to two decimal places
您可以使用以下代码将其格式化为两位小数
NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
formatter.numberStyle = NSNumberFormatterDecimalStyle;
formatter.setMaximumFractionDigits = 2;
formatter.setRoundingMode = NSNumberFormatterRoundUp;
NSString *numberString = [formatter stringFromNumber:@(10.358)];
NSLog(@"Result %@",numberString); // Result 10.36
回答by Gobra
float roundedFloat = (int)(sourceFloat * 100 + 0.5) / 100.0;
