使用 [JsonProperty] 将 Json 参数与类型为 List 的 C# 类属性匹配
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Using [JsonProperty] to match Json parameters to C# class properties which are type List
提问by Bataleon
I'm trying to deserialize the following Json response (using Json.NET):
我正在尝试反序列化以下 Json 响应（使用 Json.NET）：
[{"pollid":"1", "question":"This is a test", "start":"2011-06-28", "end":"2012-03-21", "category":"Roads", "0":"Yes", "1":"No"} … ]
Into objects of this type:
进入这种类型的对象：
class Poll
{
[JsonProperty("pollid")]
public int pollid { get; set; }
[JsonProperty("question")]
public string question { get; set; }
[JsonProperty("start")]
public DateTime start { get; set; }
[JsonProperty("end")]
public DateTime end { get; set; }
[JsonProperty("category")]
public string category { get; set; }
// PROBLEM AREA
[JsonProperty("0")] // Json parameter names are 0 to 9. How can I 'match' these to the List elements?
public List<string> polloptions { get; set; }
}
How would I use the [JsonProperty]attribute when creating a List? (Assuming the Json parameter names to be contained in this List are "0" to "9"). I've spent the last few hours trying different methods without any luck.
[JsonProperty]创建列表时如何使用该属性？（假设要包含在此列表中的 Json 参数名称为“0”到“9”）。在过去的几个小时里，我一直在尝试不同的方法，但没有任何运气。
Many thanks
非常感谢
采纳答案by nick_w
One option would be to do something like this (I took the [JsonProperty("0")]off polloptionsfirst):
一种选择是做这样的事情（我先[JsonProperty("0")]脱掉了polloptions）：
int option;
Poll poll = JsonConvert.DeserializeObject<Poll>(json);
JContainer container = (JContainer)JsonConvert.DeserializeObject(json);
poll.polloptions = container.Where(t => t as JProperty != null)
.Cast<JProperty>().Where(p => int.TryParse(p.Name, out option))
.Select(p => p.Value.Value<string>()).ToList();
The first step is to deserialize as per normal - this will take care of every property except for polloptions. The next step is to deserialize to a JContainerso that we can get at the individual tokens and create a list out of the ones with numeric names (hence the int.TryParse(p.Name, out option)).
第一步是按正常方式反序列化 - 这将处理除polloptions. 下一步是反序列化为 a ，JContainer以便我们可以获取单个标记并从具有数字名称的标记（因此是int.TryParse(p.Name, out option)）中创建一个列表。
What this will give you as a list populated with the yes/no values. If you would also like the names of the poll options as well as the values, consider this:
这将为您提供什么，作为填充是/否值的列表。如果您还想要轮询选项的名称以及值，请考虑：
Change the polloptionsproperty to:
将polloptions属性更改为：
public List<PollOption> polloptions { get; set; }
Where PollOptionis:
在哪里PollOption：
class PollOption
{
public int Name { get; set; }
public string Value { get; set; }
}
When deserializing:
反序列化时：
Poll poll = JsonConvert.DeserializeObject<Poll>(json);
JContainer container = (JContainer)JsonConvert.DeserializeObject(json);
var pollOptionNames = container.Where(t => t as JProperty != null)
.Cast<JProperty>().Where(p => int.TryParse(p.Name, out option))
.Select(p => int.Parse(p.Name)).ToList();
var pollOptionValues = container.Where(t => t as JProperty != null)
.Cast<JProperty>().Where(p => int.TryParse(p.Name, out option))
.Select(p => p.Value.Value<string>()).ToList();
poll.polloptions = pollOptionNames.Select((n, i) =>
new PollOption() { Name = n, Value = pollOptionValues[i] }).ToList();
