从 IPython 执行 Bash 命令
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execute Bash command from IPython
提问by chris
I want to source my bash environment when executing a bash command from IPython using the !operator, thus allowing me access to my defined bash functions:
我想在使用!操作符从 IPython 执行 bash 命令时获取我的 bash 环境，从而允许我访问我定义的 bash 函数：
In[2]: !<my_fancy_bash_function> <function_argument>
currently IPython is sourcing shrather than bash:
目前 IPython 正在采购sh而不是bash：
In[3]: !declare -F
sh: 1: declare: not found
How to source bashand set my environment settings from IPython?
如何bash从 IPython 获取和设置我的环境设置？
回答by Jason Sundram
Fernando Perez, creator of IPython, suggests this:
IPython 的创建者 Fernando Perez建议：
In [1]: %%bash
. ~/.bashrc
<my_fancy_bash_function> <function_argument>
This works on the current stable version (0.13.2). He admits that's a bit clunky, and welcomes pull requests. . .
这适用于当前的稳定版本 (0.13.2)。他承认这有点笨拙，并欢迎拉取请求。. .
回答by D.Shawley
If the !implementation uses IPython.utils._process_posix.systemunder the hood, then it is going to use whatever which shreturns as the processing shell. This could be a true implementation of Bourne shell - it is likely Bash in some compatibility mode on many Linuxes. On my MacBook Pro it looks like it is a raw Bash shell:
如果!实现IPython.utils._process_posix.system在幕后使用，那么它将使用任何which sh返回作为处理外壳。这可能是 Bourne shell 的真正实现——它可能在许多 Linux 上以某种兼容模式使用 Bash。在我的 MacBook Pro 上，它看起来像是一个原始的 Bash shell：
In [12]: !declare -F
In [13]: !echo $BASH
/bin/sh
In [14]: !echo $BASH_VERSION
3.2.48(1)-release
In [15]: import os
In [16]: os.environ['SHELL']
Out[16]: '/bin/zsh'
I was hoping that it would use the $SHELLenvironment variable but it does not seem to today. You can probably branch the github repo, modify the ProcessHandler.shproperty implementation to peek into os.environ['SHELL']and use this if it is set instead of calling pexpect.which('sh'). Then issue a pull request.
我希望它会使用$SHELL环境变量，但今天似乎没有。您可能可以分支 github 存储库，修改ProcessHandler.sh属性实现以查看os.environ['SHELL']并使用它，如果它被设置而不是调用pexpect.which('sh'). 然后发出拉取请求。
