Javascript 使用 .populate() 从 Mongoose 返回某些字段

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时间:2020-08-22 23:14:18  来源:igfitidea点击:

Return certain fields with .populate() from Mongoose

javascriptjsonnode.jsmongodbmongoose

提问by Sleep Deprived Bulbasaur

I'm getting returned a JSON value from MongoDB after I run my query. The problem is I do not want to return all the JSON associated with my return, I tried searching the docs and didn't find a proper way to do this. I was wondering what if it is at possible, and if so what is the proper way of doing such. Example: In the DB

运行查询后,我从 MongoDB 返回了一个 JSON 值。问题是我不想返回与我的返回相关的所有 JSON,我尝试搜索文档但没有找到正确的方法来执行此操作。我想知道如果可能的话会怎样,如果可能的话,这样做的正确方法是什么。示例:在数据库中

{
    user: "RMS",
    OS: "GNU/HURD",
    bearded: "yes",
    philosophy: {
        software: "FOSS",
        cryptology: "Necessary"
    },
    email: {
        responds: "Yes",
        address: "[email protected]"
    },
    facebook: {}
}

{
    user: "zuckerburg",
    os: "OSX",
    bearded: "no",
    philosophy: {
        software: "OSS",
        cryptology: "Optional"
    },
    email: {},
    facebook: {
        responds: "Sometimes",
        address: "https://www.facebook.com/zuck?fref=ts"
    }
} 

What would be the proper way of returning a field if it exists for a user, but if it doesn't return another field. For the example above I would want to return the [email][address]field for RMS and the [facebook][address]field for Zuckerburg. This is what I have tried to find if a field is null, but it doesn't appear to be working.

如果用户存在一个字段,但如果它不返回另一个字段,那么返回字段的正确方法是什么。对于上面的示例,我想返回[email][address]RMS 的[facebook][address]字段和 Zuckerburg的字段。如果一个字段为空,这就是我试图找到的,但它似乎不起作用。

 .populate('user' , `email.address`)
  .exec(function (err, subscription){ 
    var key;
    var f;
    for(key in subscription){
      if(subscription[key].facebook != null  ){
          console.log("user has fb");
      }
    }
  }

回答by JohnnyHK

I'm not completely clear on what you mean by "returning a field", but you can use a lean()query so that you can freely modify the output, then populate both fields and post-process the result to only keep the field you want:

我不完全清楚“返回字段”是什么意思,但您可以使用lean()查询,以便您可以自由修改输出,然后填充两个字段并对结果进行后处理以仅保留您想要的字段:

.lean().populate('user', 'email.address facebook.address')
  .exec(function (err, subscription){ 
    if (subscription.user.email.address) {
        delete subscription.user.facebook;
    } else {
        delete subscription.user.email;
    }
  });

回答by dontmentionthebackup

If you only want a few specific fields to be returned for the populated documents, you can accomplish this by passing the field name syntax as the second argument to the populate method.

如果您只想为填充的文档返回几个特定的​​字段,您可以通过将字段名称语法作为第二个参数传递给 populate 方法来实现这一点。

Model
.findOne({ _id: 'bogus' })
.populate('the_field_to_populate', 'name') // only return the Persons name
...

See Mongoose populate field selection

请参阅猫鼬填充字段选择

回答by scuencag

Try to do this:

尝试这样做:

User.find(options, '_id user email facebook').populate('facebook', '_id pos').exec(function (err, users) {

回答by S Kumar

Try to do this:

尝试这样做:

applicantListToExport: function (query, callback) {
  this
   .find(query).select({'advtId': 0})
   .populate({
      path: 'influId',
      model: 'influencer',
      select: { '_id': 1,'user':1},
      populate: {
        path: 'userid',
        model: 'User'
      }
   })
 .populate('campaignId',{'campaignTitle':1})
 .exec(callback);
}

回答by Scaraux

Now what you can do is :

现在你可以做的是:

  .populate('friends', { username: 1, age: 1})

回答by Tran Hoang Hiep

you to try :

你试试:

Post.find({_id: {$nin: [info._id]}, tags: {$in: info.tags}}).sort({_id:-1})
.populate('uid','nm')
.populate('tags','nm')
.limit(20).exec();

回答by Prashant Ghimire

Just to complement the answers above, if you want to include everything but only exclude certain attributes, you can do the following:

只是为了补充上面的答案,如果您想包含所有内容但只排除某些属性,您可以执行以下操作:

.populate('users', {password: 0, preferences: 0})

回答by Pankaj Shukla

Hi for me it worked for me i populated user field using the populate code : --->

嗨对我来说它对我有用我使用填充代码填充了用户字段:--->

async function displayMessage(req,res,next){
    try{
        let data= await Msg.find().populate("user","userName userProfileImg","User")
               if(data===null) throw "Data couldn ot be loaded server error"
        else {
            res.status(200).json(data)
        }
    }   catch(err){
            next(err)
    }
}

i am directly getting the result . Here the fields userName , userProfile image are the ones that ive required selectively and the syntax for populate is :-->

我直接得到结果。这里的字段 userName , userProfile image 是我有选择地需要的字段,填充的语法是:-->

 .populate("user field to populate","fields to display with spaces between each of them " , "modelName ")

every parameter should be in inverted comma's.

每个参数都应该用引号引起来。

Below is the output i recieve.One more thing you don't have to worry about the populating sub-document id you will automatically get them.

下面是我收到的输出。还有一件事,您不必担心填充子文档 ID,您将自动获取它们。

[
    {
        "_id": "5e8bff324beaaa04701f3bb9",
        "text": "testing message route",
        "user": {
            "_id": "5e8bf062d3c310054cf9f293",
            "userName": "boss",
            "userProfileImg": "img"
        },
        "__v": 0
    },
    {
        "_id": "5e8bff8dd4368a2858e8f771",
        "text": "testing message route second",
        "user": {
            "_id": "5e8bf062d3c310054cf9f293",
            "userName": "boss",
            "userProfileImg": "img"
        },
        "__v": 0
    },
    {
        "_id": "5e8c0c08e9bdb8209829176a",
        "text": "testing message route second",
        "user": {
            "_id": "5e8bf062d3c310054cf9f293",
            "userName": "boss",
            "userProfileImg": "img"
        },
        "__v": 0
    },
    {
        "_id": "5e8c0e0bcb63b12ec875962a",
        "text": "testing message route fourth time",
        "user": {
            "_id": "5e8bf062d3c310054cf9f293",
            "userName": "boss",
            "userProfileImg": "img"
        },
        "__v": 0
    }
]

回答by Naresh Ramoliya

you can try using below,

你可以尝试使用下面,

 Model
    .find()
    .populate({path: 'foreign_field', ['_id', 'name']}) // only return the Id and Persons name
    ...