Javascript Object.assign(...array) 的替代方案
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Alternative of Object.assign(...array)
提问by Abdennour TOUMI
Assume we have array of objects.
假设我们有对象数组。
Calling Object.assign(...array)makes an inheritance among those objects where object with index ioverride existing properties in object with index i-1
调用Object.assign(...array)在那些对象之间进行继承，其中具有索引的对象i覆盖具有索引的对象中的现有属性i-1
For example:
例如：
var array=[{interf:'IPerson',name:'Someone'},{clss:'Person',name:'Ahmed'},{student:true}];
console.log(
Object.assign(...array) // Object.assign(array[0],array[1],array[2])
)Now, using Babel with the proposed object spread syntax, we can do this statically :
现在，使用 Babel 和建议的对象传播语法，我们可以静态地做到这一点：
{...array[0],...array[1],...array[2]} // spread used for each object not for array
How to do that dynamically?
如何动态地做到这一点？
There is overlap of context of "spread syntax". I mean how to use spread syntax for both:
“传播语法”的上下文有重叠。我的意思是如何对两者使用传播语法：
- For the Array to spread elements.
- For the output literal object
{}to make inheritance
- 用于 Array 传播元素。
- 对于输出文字对象
{}进行继承
?
?
I tried {...array}and it returns {0:<array[0]>,1:<array[1]>,2:<array[2]>}which is notthe same output as Object.assign(...array).
我试着{...array}和它返回{0:<array[0]>,1:<array[1]>,2:<array[2]>}它不是作为输出相同Object.assign(...array)。
回答by Bergi
You are looking for
你正在寻找
var obj = Object.assign({}, ...array)
that creates a new object instead of mutating array[0].
创建一个新对象而不是 mutating array[0]。
回答by Michael Sherris Caley
Seems to me the method you're looking for is .concat()
在我看来你正在寻找的方法是 .concat()
Returns a new array which is a merge of the target and the source.
返回一个新数组，它是目标和源的合并。
回答by Christiyan
I thing the method you are looking for, as mentioned above, is .concat(), which creates a copie of an array or extends it with another one.
我认为你正在寻找的方法，如上所述，是 .concat()，它创建一个数组的副本或用另一个扩展它。
var a1 = [1,2,3], a2 = [];
a2 = a2.concate(a1);
// or ES5 shorten alternative
// var a1 = [1,2,3], a2 = [].concat(a1);
// or better ES6 shorten alternative
// a2 = [...a1];
a2.push(4);
console.log(a1, a2);
// a1 -> [1,2,3], a2 -> [1,2,3,4]
