C++ cout 打印十六进制而不是十进制
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cout print hex instead of decimal
提问by rahman
has it occurred to anyone that a simple std::coutmight print a value in hex format when it is supposed to format just a decimal(like an integer)?
有没有人std::cout想过，当一个简单的应该只格式化一个小数（如整数）时，它可能会以十六进制格式打印一个值？
for example, I have a line as :
例如，我有一行：
std::cout << "_Agent [" << target << "] is still among " << ((target->currWorker)->getEntities().size())<< " entities of worker[" << target->currWorker << "]" << std::endl;
std::cout << "_Agent [" << target << "] 仍然在 " << ((target->currWorker)->getEntities().size())<< " 实体的 worker[" <<目标->currWorker << "]" << std::endl;
which would print :
这将打印：
_Agent [0x2c6d530] is still among 0x1entities of worker[0x2c520f0]
_Agent [0x2c6d530] 仍然在worker[0x2c520f0] 的0x1 个实体中
Note:
笔记：
1-the said out put is sometime decimal and some times hex
1-所说的输出有时是十进制，有时是十六进制
2- the behaviour is smae even if I change ((target->currWorker)->getEntities().size())to (int)((target->currWorker)->getEntities().size())
2-即使我((target->currWorker)->getEntities().size())改为(int)((target->currWorker)->getEntities().size())
any hints?
任何提示？
thanks
谢谢
回答by Yang
You probably have set std::cout to print hex in prior in the context of your code but forget to reset. For example:
您可能已经在代码上下文中将 std::cout 设置为预先打印十六进制但忘记重置。例如：
std::cout<<std::hex<<12;
/*blah blah blah*/
std::cout<<12; //this will print in hex form still
so you have to do like the following
所以你必须做如下
std::cout<<std::dec<<12;
to print in decimal form.
以十进制形式打印。
回答by sowrov
Try to find line like this std::cout << std::showbase << std::hex;some where in your code, which sets std::coutto print output in hexadecimal with 0xbase indicator prefix.
To reset it to show decimal add this line std::cout<<std::decbefore the current cout.
尝试std::cout << std::showbase << std::hex;在代码中的某处找到这样的行，该行设置std::cout为以十六进制打印输出，带有0x基本指示符前缀。要将其重置为显示十进制std::cout<<std::dec，请在当前 cout 之前添加此行。
You can learn more about c++ io manipulators flags here
您可以在此处了解有关 c++ io 操纵器标志的更多信息
