Python 如何使用列表切片从列表中获取除第一个元素之外的所有内容
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How to get everything from the list except the first element using list slicing
提问by Omid CompSCI
So I have something that I am parsing, however here is an example of what I would like to do:
所以我有一些我正在解析的东西，但是这里是我想做的一个例子：
list = ['A', 'B', 'C']
And using list slicing have it return to me everything but the first index. So in this case:
并使用列表切片让它返回给我除了第一个索引之外的所有内容。所以在这种情况下：
['B', 'C']
I have been messing with stuff like list[:-1], list[::-1], list[0:-1], etc. But I can't seem to be able to find this out.
我一直在搞乱 list[:-1]、list[::-1]、list[0:-1] 等东西。但我似乎无法找到它。
What I am actual doing is: * I have a error message that has a error code in the beginning such as:
我实际做的是： * 我有一条错误消息，开头有一个错误代码，例如：
['226', 'Transfer', 'Complete']
and I want to just display Transfer Complete on a popup widget. Of course I am casting to a string.
我只想在弹出窗口小部件上显示传输完成。当然，我正在转换为字符串。
Thank you for all help, and if answer differs via Python 2.7.x and Python 3.x.x Please answer for both versions.
感谢您的所有帮助，如果 Python 2.7.x 和 Python 3.xx 的答案不同，请回答这两个版本。
Thanks, looked a lot around stackoverflow and python tutorials couldn't really quite get what I was looking for. Thanks for your help!
谢谢，看了很多关于 stackoverflow 和 python 教程不能真正得到我想要的东西。谢谢你的帮助！
回答by
You can just do [1:]. This will work on both versions.
你可以只做 [1:]。这将适用于两个版本。
回答by Люда Лапицкая
It can be done like this:
可以这样做：
list[1:]
