postgresql 声明变量集 = 选择
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Declare variable set = select
提问by ASA
This probably sounds like a really stupid question, but how do I declare a variable for used in a PostgreSQL 9.3 query?
这听起来可能是一个非常愚蠢的问题,但是我如何声明一个用于 PostgreSQL 9.3 查询的变量?
CREATE or replace FUNCTION public.test()
returns int4
AS
$BODY$
DECLARE
cod_process bigint :=30001;
cod_instance bigint ;
utc_log timestamp without time zone := localtimestamp;
cod_log_type varchar(100) :='information ';
txt_log_text varchar(100):= 'start process';
txt_log varchar(100):= txt_log_text||'_'||cod_process;
set cod_instance= select max(cod_instance) as cod_instance from public.instance where public.instance.cod_process=cod_process;
BEGIN
INSERT INTO public.log (cod_process, cod_instance, utc_log,cod_log_type,txt_log)
VALUES (cod_process, cod_instance, utc_log,cod_log_type,txt_log );
RETURN 11;
END;
$BODY$ LANGUAGE 'plpgsql';
ERROR: type "cod_instance" does not exist SQL state: 42704 Character: 383
ERROR: type "cod_instance" does not exist SQL state: 42704 Character: 383
回答by a_horse_with_no_name
You need to run the select using the into
clause inside the actual code block, not in the declare
block:
您需要使用into
实际代码块内的子句运行选择,而不是在declare
块中:
begin
select max(cod_instance)
into cod_instance
from public.instance
where public.instance.cod_process=cod_process;
....
end;
It's usually not such a good idea to give variables (or parameters) the same name as columns in the table. There are certain cases where this can confuse the parser. To avoid any potential problems, try to use different names for your variables, e.g. by prefixing them (e.g. l_cod_process
instead of cod_process
or l_cod_instance
instead of cod_instance
)
为变量(或参数)赋予与表中的列相同的名称通常不是一个好主意。在某些情况下,这可能会混淆解析器。为避免任何潜在问题,请尝试为变量使用不同的名称,例如通过为它们添加前缀(例如l_cod_process
代替cod_process
或l_cod_instance
代替cod_instance
)
More details on variable assignment can be found in the manual: http://www.postgresql.org/docs/current/static/plpgsql-statements.html
有关变量分配的更多详细信息,请参见手册:http: //www.postgresql.org/docs/current/static/plpgsql-statements.html
回答by Erwin Brandstetter
Your demo function would work like this:
您的演示功能将如下工作:
CREATE or replace FUNCTION public.test()
RETURNS int4 AS
$func$
DECLARE
_cod_process bigint := 30001;
_cod_instance bigint := (SELECT max(cod_instance)
FROM public.instance
WHERE cod_process = _cod_process);
_utc_log timestamp := localtimestamp;
_cod_log_type varchar(100) := 'information';
_txt_log_text varchar(100) := 'start process';
_txt_log varchar(100) := txt_log_text || '_' || cod_process;
BEGIN
INSERT INTO public.log
( cod_process, cod_instance, utc_log, cod_log_type, txt_log)
VALUES (_cod_process, _cod_instance, _utc_log, _cod_log_type, _txt_log);
RETURN 11;
END
$func$ LANGUAGE plpgsql;
Major points
要点
You cannotuse
SET
to assign a variable. That's taken to be the SQL commandSET
for setting run-time parameters.But you canassign a variable at declaration time, even use a subquery for that.
Use
LANGUAGE plpgsql
, not. It's an identifier.LANGUAGE 'plpgsql'
@a_horse_with_no_namealready wrote about naming conflicts.
Using a clean format goes a long way when debugging code ...
您不能用于
SET
分配变量。这被认为是用于设置运行时参数的SQL 命令SET
。但是您可以在声明时分配一个变量,甚至可以为此使用子查询。
使用
LANGUAGE plpgsql
,不是。它是一个标识符。LANGUAGE 'plpgsql'
@a_horse_with_no_name已经写过关于命名冲突的文章。
在调试代码时,使用干净的格式大有帮助......
But you can probably simplify to:
但您可能可以简化为:
CREATE OR REPLACE FUNCTION public.test(_cod_process bigint = 30001)
RETURNS integer AS
$func$
INSERT INTO public.log
(cod_process, cod_instance , utc_log, cod_log_type , txt_log)
SELECT , max(cod_instance), now() , 'information', 'start process_' ||
FROM public.instance
WHERE cod_process =
GROUP BY cod_process
RETURNING 11
$func$ LANGUAGE sql;
Call:
称呼:
SELECT public.test(); -- for default 30001
SELECT public.test(1234);
And depending on the actual data type of utc_log
you probably want now() AT TIME ZONE 'UTC'
:
并取决于utc_log
您可能想要的实际数据类型now() AT TIME ZONE 'UTC'
: