bash 如何在fabric（python部署工具）中的远程主机上创建一个新文件？
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How do I create a new file on a remote host in fabric (python deployment tool)?
提问by Monika Sulik
I'd like to create a file with the name passenger_wsgi.py on a remote host. I'd like to use the following string to create the file's content:
我想在远程主机上创建一个名为passenger_wsgi.py 的文件。我想使用以下字符串来创建文件的内容：
'''
import sys, os
sys.path.insert(0, "/ruby/%s/www/%s/django-projects")
sys.path.insert(0, "/ruby/%s/www/%s/django-projects/project")
import django.core.handlers.wsgi
os.environ['DJANGO_SETTINGS_MODULE'] = 'project.settings'
application = django.core.handlers.wsgi.WSGIHandler()
''' % (user,host,user,host)
The user and host variables would be parameters of the fabric function.
用户和主机变量将是结构函数的参数。
I'm a total newbie to any sort of file manipulation in python, but also I'm not really sure what the procedure should be in fabric. Should I be creating the file locally and then uploading it with fabric's put command (and removing the local version afterwards)? Should I be creating the file on the remote host with an appropriate bash command (using fabric's run)? If so, then how is it best to deal with all the " and ' in the string - will fabric escape it? Or should I be tackling this in some different manner?
我是 python 中任何类型的文件操作的新手，但我也不确定在结构中应该使用什么程序。我应该在本地创建文件，然后使用fabric 的 put 命令上传它（然后删除本地版本）？我应该使用适当的 bash 命令（使用结构的运行）在远程主机上创建文件吗？如果是这样，那么最好如何处理字符串中的所有 " 和 ' - 织物会逃脱它吗？或者我应该以某种不同的方式解决这个问题？
采纳答案by jfs
You could use append()or upload_template()functions from fabric.contrib.files
您可以使用fabric.contrib.files 中的append()或upload_template()函数
回答by Andrea Francia
Use StringIO with put:
将 StringIO 与 put 一起使用：
text = '''
import sys, os
sys.path.insert(0, "/ruby/%s/www/%s/django-projects")
sys.path.insert(0, "/ruby/%s/www/%s/django-projects/project")
import django.core.handlers.wsgi
os.environ['DJANGO_SETTINGS_MODULE'] = 'project.settings'
application = django.core.handlers.wsgi.WSGIHandler()
''' % (user, host, user, host)
import StringIO
put(StringIO.StringIO(text), "remote-path")
回答by Adam Vandenberg
What I do is have the file locally as something like "app.wsgi.template".
我所做的是在本地将文件作为“app.wsgi.template”之类的文件。
I then use tokens in the file, like:
然后我在文件中使用令牌，例如：
import sys, os
sys.path.insert(0, "/ruby/$HOST$/www/$HOST$/django-projects")
sys.path.insert(0, "/ruby/$HOST$/www/$HOST$/django-projects/project")
import django.core.handlers.wsgi
os.environ['DJANGO_SETTINGS_MODULE'] = 'project.settings'
application = django.core.handlers.wsgi.WSGIHandler()
I use fabric to "put" the file over to the remote host, then use "sed" (or equivalent functions in Python) to replace the "$HOST$" and "$USER$" tokens with the values I want.
我使用结构将文件“放置”到远程主机，然后使用“sed”（或 Python 中的等效函数）将“$HOST$”和“$USER$”标记替换为我想要的值。
run("sed -i backup -e 's/$USER$/%s' -e 's/$HOST$/%s' app.wsgi.template" % (user, host))
run("mv app.wsgi.template app.wsgi")
回答by Moses Liao GZ
StringIO with put works with a little bit of editing. Try this:
带有 put 的 StringIO 需要一些编辑。尝试这个：
put(StringIO.StringIO(
'''
import sys, os
sys.path.insert(0, "/ruby/%s/www/%s/django-projects")
sys.path.insert(0, "/ruby/%s/www/%s/django-projects/project")
import django.core.handlers.wsgi
os.environ['DJANGO_SETTINGS_MODULE'] = 'project.settings'
application = django.core.handlers.wsgi.WSGIHandler()
''' % (user,host,user,host)), "remote-path")
if you have an issue with permissions, try this:
如果您有权限问题，请尝试以下操作：
put(StringIO.StringIO(
'''
import sys, os
sys.path.insert(0, "/ruby/%s/www/%s/django-projects")
sys.path.insert(0, "/ruby/%s/www/%s/django-projects/project")
import django.core.handlers.wsgi
os.environ['DJANGO_SETTINGS_MODULE'] = 'project.settings'
application = django.core.handlers.wsgi.WSGIHandler()
''' % (user,host,user,host)), "remote-path", use_sudo=True)
