Python 我只想返回列表中的奇数
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I want to return only the odd numbers in a list
提问by I liek to c0d3
My issue here is that the code filters out the even numbers correctly which is what I want, however it stops at seven and doesn't display number 9 which is what I would expect it to do. I've tried going over my code but I can't seem to find the issue
我的问题是代码正确过滤了偶数，这正是我想要的，但是它停在 7 处并且不显示数字 9，这是我期望它做的。我试过检查我的代码，但我似乎找不到问题
def remove_even(numbers) :
new_list = []
for i in range(0,len(numbers)-1) :
if i % 2 != 0 :
new_list.append(i)
return new_list
l = [1,2,3,4,5,6,7,8,9,10]
print(remove_even(l))
回答by Cory Kramer
You should just directly loop through your values instead of indices
您应该直接遍历您的值而不是索引
for i in numbers:
Otherwise if you wanted to use rangeyou would have to index into your list
否则，如果您想使用range，则必须索引到您的list
for i in range(0, len(numbers)):
if numbers[i] % 2 != 0 :
new_list.append(numbers[i])
For brevity, list comprehensions are well-suited for this type of task
为简洁起见，列表推导式非常适合此类任务
>>> new_list = [num for num in l if num % 2 == 1]
>>> new_list
[1, 3, 5, 7, 9]
回答by e4c5
回答by Ajay Rawat
This is because you are starting your range() function of your for loop from 0 and ending at len(numbers)-1 (which is 9 in your case), python range() already will run till end-1:
这是因为您从 0 开始 for 循环的 range() 函数并以 len(numbers)-1（在您的情况下为 9）结束，python range() 已经将运行到 end-1：
for eg:
例如：
for i in range(0,9):
print(i)
will print no's: 0 1 2 3 4 5 6 7 8
将打印编号：0 1 2 3 4 5 6 7 8
and that's why your 9 is not here in the output.
这就是为什么您的 9 不在输出中的原因。
you don't have to start your loop from 0. If you are starting from 0 you can arrange your for loop like this:
你不必从 0 开始你的循环。如果你从 0 开始，你可以像这样安排你的 for 循环：
1)
1)
for i in range(0, len(numbers)+1)
2)Or you can code like more pythonic way.
2）或者你可以像更pythonic的方式编码。
def remove_even(numbers) :
new_list = []
for i in numbers :
if i % 2 != 0 :
new_list.append(i)
return new_list
回答by Mike Turner
#simpliest way of doing it
mylist = [1,2,3,4,5,6,7,8,9,10,11]
for x in mylist:
if x % 2 == 1: #this displays odd numbers
print(x)
回答by Gauthier Feuillen
numbers = [1,2,3,4,5,6,7,8,9,10]
odds = [i for i in numbers if i%2!=0]
