Python __init__() 得到了一个意外的关键字参数“用户”
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__init__() got an unexpected keyword argument 'user'
提问by noben
i am using Django to create a user and an object when the user is created. But there is an error
我正在使用 Django 在创建用户时创建一个用户和一个对象。但是有一个错误
__init__() got an unexpected keyword argument 'user'
__init__() got an unexpected keyword argument 'user'
when calling the register()function in view.py.
The function is:
register()在 view.py 中调用函数时。功能是：
def register(request):
'''signup view'''
if request.method=="POST":
form=RegisterForm(request.POST)
if form.is_valid():
username=form.cleaned_data["username"]
email=form.cleaned_data["email"]
password=form.cleaned_data["password"]
user=User.objects.create_user(username, email, password)
user.save()
return HttpResponseRedirect('/keenhome/accounts/login/')
else:
form = RegisterForm()
return render_to_response("polls/register.html", {'form':form}, context_instance=RequestContext(request))
#This is used for reinputting if failed to register
else:
form = RegisterForm()
return render_to_response("polls/register.html", {'form':form}, context_instance=RequestContext(request))
and the object class is:
对象类是：
class LivingRoom(models.Model):
'''Living Room object'''
user = models.OneToOneField(User)
def __init__(self, temp=65):
self.temp=temp
TURN_ON_OFF = (
('ON', 'On'),
('OFF', 'Off'),
)
TEMP = (
('HIGH', 'High'),
('MEDIUM', 'Medium'),
('LOW', 'Low'),
)
on_off = models.CharField(max_length=2, choices=TURN_ON_OFF)
temp = models.CharField(max_length=2, choices=TEMP)
#signal function: if a user is created, add control livingroom to the user
def create_control_livingroom(sender, instance, created, **kwargs):
if created:
LivingRoom.objects.create(user=instance)
post_save.connect(create_control_livingroom, sender=User)
The Django error page notifies the error information:
user=User.objects.create_user(username, email, password)and
LivingRoom.objects.create(user=instance)
Django 错误页面通知错误信息：
user=User.objects.create_user(username, email, password)和
LivingRoom.objects.create(user=instance)
I tried to search this problem, finding some cases, but still cannot figure out how to solve it.
我试图搜索这个问题，找到一些案例，但仍然无法弄清楚如何解决它。
采纳答案by shad0w_wa1k3r
You can't do
你不能做
LivingRoom.objects.create(user=instance)
because you have an __init__method that does NOT take useras argument.
因为你有一个__init__不user作为参数的方法。
You need something like
你需要类似的东西
#signal function: if a user is created, add control livingroom to the user
def create_control_livingroom(sender, instance, created, **kwargs):
if created:
my_room = LivingRoom()
my_room.user = instance
回答by bruno desthuilliers
LivingRoom.objects.create()calls LivingRoom.__init__()- as you might have noticed if you had read the traceback - passing it the same arguments. To make a long story short, a Django models.Modelsubclass's initializer is best left alone, or should accept *args and **kwargs matching the model's meta fields. The correct way to provide default values for fields is in the field constructor using the defaultkeyword as explained in the FineManual.
LivingRoom.objects.create()调用LivingRoom.__init__()- 如果您已经阅读了回溯，您可能已经注意到 - 将相同的参数传递给它。长话短说，Djangomodels.Model子类的初始值设定项最好单独保留，或者应该接受与模型的元字段匹配的 *args 和 **kwargs。为字段提供默认值的正确方法是在字段构造函数中使用defaultFineManual 中解释的关键字。
回答by Luis Berrocal
I got the same error.
我得到了同样的错误。
On my view I was overriding get_form_kwargs() like this:
在我看来，我正在像这样覆盖 get_form_kwargs()：
class UserAccountView(FormView):
form_class = UserAccountForm
success_url = '/'
template_name = 'user_account/user-account.html'
def get_form_kwargs(self):
kwargs = super(UserAccountView, self).get_form_kwargs()
kwargs.update({'user': self.request.user})
return kwargs
But on my form I failed to override the init() method. Once I did it. Problem solved
但是在我的表单上我没有覆盖init() 方法。一旦我做到了。问题解决了
class UserAccountForm(forms.Form):
first_name = forms.CharField(label='Your first name', max_length=30)
last_name = forms.CharField(label='Your last name', max_length=30)
email = forms.EmailField(max_length=75)
def __init__(self, *args, **kwargs):
user = kwargs.pop('user')
super(UserAccountForm, self).__init__(*args, **kwargs)
回答by Phillip Kigenyi
Check your imports. There could be two classes with the same name. Either from your code or from a library you are using. Personally that was the issue.
检查您的进口。可能有两个具有相同名称的类。来自您的代码或您正在使用的库。就个人而言，这就是问题所在。
