使用 scandir() 在目录中查找文件夹 (PHP)
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Using scandir() to find folders in a directory (PHP)
提问by Ben McRae
I am using this peice of code:
我正在使用以下代码：
$target = 'extracted/' . $name[0];
$scan = scandir($target);
To scan the directory of a folder which is used for zip uploads. I want to be able to find all the folders inside my $targetfolder so I can delete them and their contents, leaving only the files in the $targetdirectory.
扫描用于 zip 上传的文件夹的目录。我希望能够在我的$target文件夹中找到所有文件夹，以便我可以删除它们及其内容，只留下目录中的$target文件。
Once I have returned the contents of the folder, I don't know how to differentiate between the folders and the files to be able to delete the folders.
一旦我返回了文件夹的内容，我不知道如何区分文件夹和文件才能删除文件夹。
Also, I have been told that the rmdir()function can't delete folders which have content inside them, is there any way around this?
另外，我被告知该rmdir()功能无法删除其中包含内容的文件夹，有什么办法可以解决这个问题吗？
Thanks, Ben.
谢谢，本。
回答by travis-146
To determine whether or not you have a folder or file use the functions is_dir()and is_file()
要确定您是否有文件夹或文件，请使用函数is_dir()和is_file()
For example:
例如：
$path = 'extracted/' . $name[0];
$results = scandir($path);
foreach ($results as $result) {
if ($result === '.' or $result === '..') continue;
if (is_dir($path . '/' . $result)) {
//code to use if directory
}
}
回答by Dominic
Better to use DirectoryIterator
$path = 'extracted'; // '.' for current
foreach (new DirectoryIterator($path) as $file) {
if ($file->isDot()) continue;
if ($file->isDir()) {
print $file->getFilename() . '<br />';
}
}
回答by Hawk Kroeger
回答by alex
$directories = scandir('images');
foreach($directories as $directory){
if($directory=='.' or $directory=='..' ){
echo 'dot';
}else{
if(is_dir($directory)){
echo $directory .'<br />';
}
}
}
a simpler and perhaps faster version
一个更简单，也许更快的版本
回答by ジェン?
scandir will scan the entire directory, you can manually filter.
scandir 会扫描整个目录，可以手动过滤。
but if you are lazy like I am, then use glob
但如果你像我一样懒惰，那么使用 glob
$scan = glob($target."/*",GLOB_ONLYDIR);
and it will output an array of all your directories of your target.
它将输出目标的所有目录的数组。
回答by inrsaurabh
To get all the files in all the sub, sub folders
获取所有子、子文件夹中的所有文件
function myfunction($dir){
foreach ($dir as $dirname => $file) {
if(is_dir($file) && $file != '.' && $file != '..' ) {
// echo $file;
$newDir = scandir($file);
myfunction($newDir);
}elseif($file !='.' && $file != '..'){
echo "<br>File name is ---";
echo $file;
}
} // end foreach
} //function ends
$dirpass = scandir($mypath3); // set directory
echo myfunction($dirpass); // pass directory
We will get the result like below (plz ignore file names )
我们将得到如下结果（请忽略文件名）
File name is ----->index.PHP
File name is -----> 100000045 Invoices Sales Magento Admin.png
File name is -----> 100000142 Orders Sales Magento Admin(1).png
File name is -----> 100000142 Orders Sales Magento Admin.png
File name is ----->hrc-siberian-tiger-2-jpg_21253111.jpg
File name is ----->images (3rd copy).jpeg
File name is ----->images (4th copy).jpeg
File name is ----->images (5th copy).jpeg
File name is ----->images (another copy).jpeg
File name is ----->images (copy).jpeg
File name is ----->images.jpeg
File name is ----->JPEG_example_JPG_RIP_100.jpg
File name is ----->preload
File name is ----->Stonehenge (3rd copy).jpg
File name is ----->Stonehenge (4th copy).jpg
File name is ----->Stonehenge (5th copy).jpg
File name is ----->Stonehenge (another copy).jpg
File name is ----->Stonehenge (copy).jpg
File name is ----->Stonehenge.jpg
回答by user889030
here is one function i used mostly to parse archives and directories
这是我主要用来解析档案和目录的一个函数
function scan_full_dir($dir,$child=false){
$dir_content_list = scandir($dir);
foreach($dir_content_list as $value)
{
if($value === '.' || $value === '..') {continue;}
// check if we have file
if(is_file($dir.'/'.$value)) {
echo '<br> File Name --> '.$value;
continue;
}
// check if we have directory
if (is_dir($dir.'/'.$value)) {
if(!$child){
echo '<br> parent --> '.$value;
}else{
echo '<br> child of '.$child.' --> '.$value;
}
scan_full_dir($dir.'/'.$value,$value);
}
}
}
output sample
输出样本
parent --> fonts
File Name --> standard
parent --> steps
child of steps --> pcb
File Name --> .attrlist.sum
File Name --> .profile.sum
File Name --> .stephdr.sum
File Name --> attrlist
child of pcb --> netlists
child of netlists --> cadnet
File Name --> .netlist.sum
File Name --> netlist
File Name --> profile
File Name --> stephdr
// to scan dir
// 扫描目录
scan_full_dir('path/of/myfolder');
// to scan archive without opening it , supported formats : gz, zip, tar and bz files.
// 无需打开即可扫描存档，支持的格式：gz、zip、tar 和 bz 文件。
scan_full_dir('phar://uploads/youarchive.zip);
回答by ジェン?
You also wanted to remove items if they were inside that directory. rmdir does not allow you to remove directories containing files. But there is a simple sollution.
您还想删除位于该目录中的项目。rmdir 不允许您删除包含文件的目录。但是有一个简单的解决方案。
array_map('unlink', glob($target.'/*/*'));
array_map('rmdir',glob($target."/*",GLOB_ONLYDIR));
First it will unlink all the files in all sub-directories.
Secondly it will remove all directories, because they contain no files.
首先它将取消链接所有子目录中的所有文件。
其次，它将删除所有目录，因为它们不包含任何文件。
If you got sub-sub-directories, then you should add another 2 lines like this:
如果您有子目录，那么您应该添加另外两行，如下所示：
array_map('unlink', glob($target.'/*/*/*')); //remove sub-sub-files
array_map('rmdir',glob($target."/*/*",GLOB_ONLYDIR)); //remove sub-sub-directories
array_map('unlink', glob($target.'/*/*')); //remove sub-files
array_map('rmdir',glob($target."/*",GLOB_ONLYDIR)); //remove sub-directories
回答by Andreas Bergstr?m
The quick and dirty way:
快速而肮脏的方式：
$folders = glob("<path>/*", GLOB_ONLYDIR);
A more versatile and object-oriented solution, inspired by earlier answers using DirectoryIterator but slightly more concise and general purpose:
一个更通用和面向对象的解决方案，灵感来自使用 DirectoryIterator 的早期答案，但更简洁和通用：
$path = '<path>';
$folders = [];
foreach (new \DirectoryIterator($path) as $file)
{
if (!$file->isDot() && $file->isDir())
{
$folders[] = $file;
}
}
