C++ 调用基类的运算符...安全吗？
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calling operators of base class... safe?
提问by smerlin
Is following pattern ok/safe ? Or are there any shortcomings ? (I also use it for equality operators)
以下模式可以/安全吗？或者有什么缺点？（我也将它用于相等运算符）
Derived& operator=(const Derived& rhs)
{
static_cast<Base&>(*this) = rhs;
// ... copy member variables of Derived
return *this;
}
回答by Moo-Juice
This is fine, but it's a lot more readable IMHO to call the base-class by name:
这很好，但恕我直言，按名称调用基类更具可读性：
Base::operator = (rhs);
回答by peoro
Yes, it's safe.
是的，它很安全。
A different syntax to do the same thing could be:
做同样事情的不同语法可能是：
Base::operator=( rhs );
回答by olive007
That's better to use
这样使用更好
Base::operator=(rhs);
because if your base class have a pure virtual method the static_cast is not allowed.
因为如果您的基类具有纯虚方法，则不允许使用 static_cast。
class Base {
// Attribute
public:
virtual void f() = 0;
protected:
Base& operator(const Base&);
}
class Derived {
public:
virtual void f() {};
Derived& operator=(const Derived& src) {
Base::operator=(src); // work
static_cast<Base&>(*this) = src; // didn't work
}
}
