C# 验证电子邮件以不盲目接受电子邮件的最简单正则表达式是什么？
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原文地址: http://stackoverflow.com/questions/742451/
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What is the simplest regular expression to validate emails to not accept them blindly?
提问by eKek0
When users create an account on my site I want to make server validation for emails to not accept everyinput.
当用户在我的网站上创建帐户时，我想对电子邮件进行服务器验证以不接受所有输入。
I will send a confirmation, in a way to do a handshake validation.
我将发送确认，以某种方式进行握手验证。
I am looking for something simple, not the best, but not too simple that doesn't validate anything. I don't know where limitation must be, since any regular expression will not do the correct validation because is not possible to do it with regular expressions.
我正在寻找一些简单的东西，不是最好的，但也不是太简单的不能验证任何东西的东西。我不知道限制在哪里，因为任何正则表达式都不会进行正确的验证，因为使用正则表达式是不可能的。
I'm trying to limit the sintax and visual complexity inherent to regular expressions, because in this case any will be correct.
我试图限制正则表达式固有的语法和视觉复杂性，因为在这种情况下，任何都是正确的。
What regexp can I use to do that?
我可以使用什么正则表达式来做到这一点？
采纳答案by chaos
^\S+@\S+$
回答by Guffa
It's possible to write a regular expression that only accept email addresses that follow the standards. However, there are some email addresses out there that doesn't strictly follow the standards, but still work.
可以编写一个只接受符合标准的电子邮件地址的正则表达式。但是，有一些电子邮件地址没有严格遵守标准，但仍然有效。
Here are some simple regular expressions for basic validation:
以下是一些用于基本验证的简单正则表达式：
Contains a @ character:
包含 @ 字符：
@
Contains @ and a period somewhere after it:
包含 @ 和它后面的一个句点：
@.*?\.
Has at least one character before the @, before the period and after it:
在@ 之前、句点之前和之后至少有一个字符：
.+@.+\..+
Has only one @, at least one character before the @, before the period and after it:
只有一个@，在@ 之前，句点之前和之后至少有一个字符：
^[^@]+@[^@]+\.[^@]+$
User AmoebaMan17 suggests this modification to eliminate whitespace:
用户 AmoebaMan17 建议进行此修改以消除空格：
^[^@\s]+@[^@\s]+\.[^@\s]+$
And for accepting only one period:
并且只接受一个时期：
^[^@\s]+@[^@\s\.]+\.[^@\.\s]+$
回答by JP Alioto
Here's the one that complies with RFC 2822 Section 3.4.1...
这是符合RFC 2822 Section 3.4.1...
(?:[a-z0-9!#$%&'*+/=?^_`{|}~-]+(?:\.[a-z0-9!#$%&'*+/=?^_`{|}~-]+)*|"(?:[\x01-\x08\x0b\x0c\x0e-\x1f\x21\x23-\x5b\x5d-\x7f]|\[\x01-\x09\x0b\x0c\x0e-\x7f])*")@(?:(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\.)+[a-z0-9](?:[a-z0-9-]*[a-z0-9])?|\[(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?|[a-z0-9-]*[a-z0-9]:(?:[\x01-\x08\x0b\x0c\x0e-\x1f\x21-\x5a\x53-\x7f]|\[\x01-\x09\x0b\x0c\x0e-\x7f])+)\])
Just in case you are curious. :)
以防万一你好奇。:)
回答by coto
^[a-zA-Z0-9_.+-]+@[a-zA-Z0-9-]+.[a-zA-Z0-9-.]+$
^[a-zA-Z0-9_.+-]+@[a-zA-Z0-9-]+.[a-zA-Z0-9-.]+$
- Only 1 @
- Several domains and subdomains
- 只有1个 @
- 多个域和子域
回答by Carl Howarth
I think this little tweak to the expression by AmoebaMan17 should stop the address from starting/ending with a dot and also stop multiple dots next to each other. Trying not to make it complex again whilst eliminating a common issue.
我认为 AmoebaMan17 对表达式的这个小调整应该可以阻止地址以点开头/结尾，并且还可以阻止多个点相邻。在消除一个常见问题的同时，尽量不让它再次变得复杂。
(?!.*\.\.)(^[^\.][^@\s]+@[^@\s]+\.[^@\s\.]+$)
It appears to be working (but I am no RegEx-pert). Fixes my issue with users copy&pasting email addresses from the end of sentences that terminate with a period.
它似乎正在工作（但我不是 RegEx-pert）。解决了用户从句号结尾处复制和粘贴电子邮件地址的问题。
i.e: Here's my new email address [email protected].
即：这是我的新电子邮件地址 [email protected]。
