使用 Java 上传和 POST 文件到 PHP 页面
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原文地址: http://stackoverflow.com/questions/1314249/
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Upload and POST file to PHP page with Java
提问by
I need a way to upload a file and POST it into php page...
我需要一种上传文件并将其发布到 php 页面的方法...
My php page is:
我的 php 页面是：
<?php
$maxsize = 10485760;
$array_estensioni_ammesse=array('.tmp');
$uploaddir = 'uploads/';
if (is_uploaded_file($_FILES['file']['tmp_name']))
{
if($_FILES['file']['size'] <= $maxsize)
{
$estensione = strtolower(substr($_FILES['file']['name'], strrpos($_FILES['file']['name'], "."), strlen($_FILES['file']['name'])-strrpos($_FILES['file']['name'], ".")));
if(!in_array($estensione, $array_estensioni_ammesse))
{
echo "File is not valid!\n";
}
else
{
$uploadfile = $uploaddir . basename($_FILES['file']['name']);
echo "File ". $_FILES['file']['name'] ." uploaded successfully.\n";
if (move_uploaded_file($_FILES['file']['tmp_name'], $uploadfile))
{
echo "File is valid, and was successfully moved.\n";
}
else
print_r($_FILES);
}
}
else
echo "File is not valid!\n";
}
else
{
echo "Upload Failed!!!";
print_r($_FILES);
}
?>
and i use this java code in my desktop application:
我在我的桌面应用程序中使用这个 java 代码：
HttpURLConnection httpUrlConnection = (HttpURLConnection)new URL("http://www.mypage.org/upload.php").openConnection();
httpUrlConnection.setDoOutput(true);
httpUrlConnection.setRequestMethod("POST");
OutputStream os = httpUrlConnection.getOutputStream();
Thread.sleep(1000);
BufferedInputStream fis = new BufferedInputStream(new FileInputStream("tmpfile.tmp"));
long totalByte = fis.available();
long byteTrasferred = 0;
for (int i = 0; i < totalByte; i++) {
os.write(fis.read());
byteTrasferred = i + 1;
}
os.close();
BufferedReader in = new BufferedReader(
new InputStreamReader(
httpUrlConnection.getInputStream()));
String s = null;
while ((s = in.readLine()) != null) {
System.out.println(s);
}
in.close();
fis.close();
But I receive always the "Upload Failed!!!" message.
但我总是收到“上传失败！！！” 信息。
回答by Byron Whitlock
You are not using the correct HTML file upload semantics. You are just posting a bunch of data to the url.
您没有使用正确的 HTML 文件上传语义。您只是将一堆数据发布到网址。
You have 2 option here:
您在这里有 2 个选择：
- You can keep the java code as-is, and change the php code to just read the raw POST as a file.
- Change the java code to do a real file upload possibly using a common library.
- 您可以按原样保留 java 代码，并将 php 代码更改为仅将原始 POST 作为文件读取。
- 更改 java 代码以执行可能使用公共库的真实文件上传。
I'd recommend changing the java code to do this in a standards compliant way.
我建议更改 java 代码以符合标准的方式执行此操作。
回答by Chris Thompson
回答by Daniil
All above answers are 100% correct. You can also use plain sockets, in which case your method would look like this:
以上所有答案100%正确。您还可以使用普通套接字，在这种情况下，您的方法将如下所示：
// Compose the request header
StringBuffer buf = new StringBuffer();
buf.append("POST ");
buf.append(uploader.getUploadAction());
buf.append(" HTTP/1.1\r\n");
buf.append("Content-Type: multipart/form-data; boundary=");
buf.append(boundary);
buf.append("\r\n");
buf.append("Host: ");
buf.append(uploader.getUploadHost());
buf.append(':');
buf.append(uploader.getUploadPort());
buf.append("\r\n");
buf.append("Connection: close\r\n");
buf.append("Cache-Control: no-cache\r\n");
// Add cookies
List cookies = uploader.getCookies();
if (!cookies.isEmpty())
{
buf.append("Cookie: ");
for (Iterator iterator = cookies.iterator(); iterator.hasNext(); )
{
Parameter parameter = (Parameter)iterator.next();
buf.append(parameter.getName());
buf.append('=');
buf.append(parameter.getValue());
if (iterator.hasNext())
buf.append("; ");
}
buf.append("\r\n");
}
buf.append("Content-Length: ");
// Request body
StringBuffer body = new StringBuffer();
List fields = uploader.getFields();
for (Iterator iterator = fields.iterator(); iterator.hasNext();)
{
Parameter parameter = (Parameter) iterator.next();
body.append("--");
body.append(boundary);
body.append("\r\n");
body.append("Content-Disposition: form-data; name=\"");
body.append(parameter.getName());
body.append("\"\r\n\r\n");
body.append(parameter.getValue());
body.append("\r\n");
}
body.append("--");
body.append(boundary);
body.append("\r\n");
body.append("Content-Disposition: form-data; name=\"");
body.append(uploader.getImageFieldName());
body.append("\"; filename=\"");
body.append(file.getName());
body.append("\"\r\n");
body.append("Content-Type: image/pjpeg\r\n\r\n");
String boundary = "WHATEVERYOURDEARHEARTDESIRES";
String lastBoundary = "\r\n--" + boundary + "--\r\n";
long length = file.length() + (long) lastBoundary.length() + (long) body.length();
long total = buf.length() + body.length();
buf.append(length);
buf.append("\r\n\r\n");
// Upload here
InetAddress address = InetAddress.getByName(uploader.getUploadHost());
Socket socket = new Socket(address, uploader.getUploadPort());
try
{
socket.setSoTimeout(60 * 1000);
uploadStarted(length);
PrintStream out = new PrintStream(new BufferedOutputStream(socket.getOutputStream()));
out.print(buf);
out.print(body);
// Send the file
byte[] bytes = new byte[1024 * 65];
int size;
InputStream in = new BufferedInputStream(new FileInputStream(file));
try
{
while ((size = in.read(bytes)) > 0)
{
total += size;
out.write(bytes, 0, size);
transferred(total);
}
}
finally
{
in.close();
}
out.print(lastBoundary);
out.flush();
// Read the response
BufferedReader reader = new BufferedReader(new InputStreamReader(socket.getInputStream()));
while (reader.readLine() != null);
}
finally
{
socket.close();
}
回答by Lauri Lehtinen
I realize this is a bit old but I just posted an answer to a similar questionthat should be applicable here as well. It includes code similar to Daniil's, but uses HttpURLConnection instead of a Socket.
我意识到这有点旧，但我刚刚发布了一个类似问题的答案，该答案也适用于此。它包含类似于 Daniil 的代码，但使用 HttpURLConnection 而不是 Socket。
回答by user622169
This is an old thread, but for the benefit of others, here is a fully workingexample of exactly what the op asks for:
这是一个旧线程，但为了其他人的利益，这里有一个完整的示例，说明操作所要求的内容：
PHP server code:
PHP服务器代码：
<?php
$target_path = "uploads/";
$target_path = $target_path . basename( $_FILES['uploadedfile']['name']);
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
echo "The file ". basename( $_FILES['uploadedfile']['name'])." has been uploaded";
} else{
echo "There was an error uploading the file, please try again!";
}
?>
Java client code:
Java客户端代码：
import java.io.OutputStream;
import java.io.InputStream;
import java.net.URLConnection;
import java.net.URL;
import java.net.Socket;
public class Main {
private final String CrLf = "\r\n";
public static void main(String[] args) {
Main main = new Main();
main.httpConn();
}
private void httpConn() {
URLConnection conn = null;
OutputStream os = null;
InputStream is = null;
try {
URL url = new URL("http://localhost/test/post.php");
System.out.println("url:" + url);
conn = url.openConnection();
conn.setDoOutput(true);
String postData = "";
InputStream imgIs = getClass().getResourceAsStream("/test.jpg");
byte[] imgData = new byte[imgIs.available()];
imgIs.read(imgData);
String message1 = "";
message1 += "-----------------------------4664151417711" + CrLf;
message1 += "Content-Disposition: form-data; name=\"uploadedfile\"; filename=\"test.jpg\""
+ CrLf;
message1 += "Content-Type: image/jpeg" + CrLf;
message1 += CrLf;
// the image is sent between the messages in the multipart message.
String message2 = "";
message2 += CrLf + "-----------------------------4664151417711--"
+ CrLf;
conn.setRequestProperty("Content-Type",
"multipart/form-data; boundary=---------------------------4664151417711");
// might not need to specify the content-length when sending chunked
// data.
conn.setRequestProperty("Content-Length", String.valueOf((message1
.length() + message2.length() + imgData.length)));
System.out.println("open os");
os = conn.getOutputStream();
System.out.println(message1);
os.write(message1.getBytes());
// SEND THE IMAGE
int index = 0;
int size = 1024;
do {
System.out.println("write:" + index);
if ((index + size) > imgData.length) {
size = imgData.length - index;
}
os.write(imgData, index, size);
index += size;
} while (index < imgData.length);
System.out.println("written:" + index);
System.out.println(message2);
os.write(message2.getBytes());
os.flush();
System.out.println("open is");
is = conn.getInputStream();
char buff = 512;
int len;
byte[] data = new byte[buff];
do {
System.out.println("READ");
len = is.read(data);
if (len > 0) {
System.out.println(new String(data, 0, len));
}
} while (len > 0);
System.out.println("DONE");
} catch (Exception e) {
e.printStackTrace();
} finally {
System.out.println("Close connection");
try {
os.close();
} catch (Exception e) {
}
try {
is.close();
} catch (Exception e) {
}
try {
} catch (Exception e) {
}
}
}
}
you can figure out how to adapt it for your site, but I have tested the above code and it works. I can't take credit for it though >> See Original Post
您可以弄清楚如何为您的网站调整它，但我已经测试了上面的代码并且它有效。虽然我不能相信它 >>见原帖
回答by BoltzmannBrain
Even though the thread is very old, there may still be someone around looking for a more easy way to solve this problem (like me :))
尽管该线程很旧，但可能仍然有人在寻找解决此问题的更简单方法（例如我:)）
After some research I found a way to uplaod a file without changing the original poster's Java-Code. You just have to use the following PHP-code:
经过一番研究，我找到了一种无需更改原始发布者的 Java 代码即可上传文件的方法。您只需要使用以下 PHP 代码：
<?php
$filename="abc.xyz";
$fileData=file_get_contents('php://input');
$fhandle=fopen($filename, 'wb');
fwrite($fhandle, $fileData);
fclose($fhandle);
echo("Done uploading");
?>
This code is just fetching the raw data sent by the java-application and writing it into a file. There is, however one problem: You dont get the original filename, so you have to transmit it somehow else.
这段代码只是获取 java 应用程序发送的原始数据并将其写入文件。但是有一个问题：您没有获得原始文件名，因此您必须以其他方式传输它。
I solved this problem by using a GET-Parameter, which makes a little change in the Java-code necessary:
我通过使用 GET 参数解决了这个问题，这需要对 Java 代码进行一些更改：
HttpURLConnection httpUrlConnection = (HttpURLConnection)new URL("http://www.mypage.org/upload.php").openConnection();
changes to
更改为
HttpURLConnection httpUrlConnection = (HttpURLConnection)new URL("http://www.mypage.org/upload.php?filename=abc.def").openConnection();
In your PHP-script you change the line
在您的 PHP 脚本中，您更改了该行
$filename="abc.xyz";
to
到
$filename=$_GET['filename'];
This solution doesn't use any external librarys and seems to me much more simple than some of the other posted ones...
这个解决方案不使用任何外部库，在我看来比其他一些发布的要简单得多......
Hope I could help anyone:)
希望我可以帮助任何人:)
