java 找到最多 2 个以上数字的更方便的方法？
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More convenient way to find the max of 2+ numbers?
提问by Sartheris Stormhammer
I want code that accepts more than 2 integers and prints out the biggest one. I used Math.MAXbut the problem is that it accepts only 2 integers by default, and you can't print all the ints in it. So I had to make it like this:
我想要接受 2 个以上整数并打印出最大整数的代码。我用过，Math.MAX但问题是它默认只接受 2 个整数，而且你不能打印其中的所有整数。所以我不得不这样做：
int max = Math.max(a, Math.max(b, Math.max(c, Math.max(d, e))));
Is there a better method to do this?
有没有更好的方法来做到这一点？
回答by NPE
You could use varargs:
你可以使用可变参数：
public static Integer max(Integer... vals) {
Integer ret = null;
for (Integer val : vals) {
if (ret == null || (val != null && val > ret)) {
ret = val;
}
}
return ret;
}
public static void main(String args[]) {
System.out.println(max(1, 2, 3, 4, 0, -1));
}
Alternatively:
或者：
public static int max(int first, int... rest) {
int ret = first;
for (int val : rest) {
ret = Math.max(ret, val);
}
return ret;
}
回答by Boris the Spider
You can use a simple loop:
您可以使用一个简单的循环：
public Integer max(final Collection<Integer> ints) {
Integer max = Integer.MIN_VALUE;
for (Integer integer : ints) {
max = Math.max(max, integer);
}
return max;
}
