cpp / c++ 获取指针值或去指针化指针
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/14420257/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
cpp / c++ get pointer value or depointerize pointer
提问by Rasmus
I was wondering if it's possible to make a pointer not a pointer..
我想知道是否有可能使指针不是指针..
The problem is I have a function that accepts a pointer for an paramater for me to easily get a value to that pointer. It's a simple int so I was wondering if I could just get that value without needing to send around a pointer wherever I want the value to land.
问题是我有一个函数，它接受一个参数的指针，以便我轻松获取该指针的值。这是一个简单的 int，所以我想知道是否可以直接获取该值，而无需将指针发送到我想要该值所在的任何位置。
I don't want the function to return the value as an int as it's giving a value to 2 pointers!
我不希望该函数将值作为 int 返回，因为它为 2 个指针提供了一个值！
回答by James McDonnell
To get the value of a pointer, just de-reference the pointer.
要获取指针的值，只需取消对指针的引用。
int *ptr;
int value;
*ptr = 9;
value = *ptr;
value is now 9.
值现在是 9。
I suggest you read more about pointers, this is their base functionality.
我建议你阅读更多关于指针的内容，这是它们的基本功能。
