将文件名中包含特定字符串的目录中的所有文件复制到 Bash 中的不同目录
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Copy all files in a directory with a particular string in the filename to different directory in Bash
提问by Suku
For example, a directory could contain the files
例如，一个目录可以包含文件
12_foo9.dat
34foo32.txt
24foobar.png
997_bar.txt
and I would like to copy the files with 'foo' in the file names to a separate directory so that it would contain those first three files but not the fourth.
我想将文件名中带有 'foo' 的文件复制到一个单独的目录中，以便它包含前三个文件而不是第四个文件。
I've looked around but haven't figured out a way to do this. The directory has a very large number of files, but only 1% or so that I need to copy.
我环顾四周，但还没有想出办法做到这一点。该目录有大量文件，但只有 1% 左右需要复制。
Thanks
谢谢
回答by Suku
$ mkdir NEWDIR
$ touch foo_file file_foo file_foo_file
$ ls
NEWDIR file_foo file_foo_file foo_file
$ cp -v *foo NEWDIR/
file_foo -> NEWDIR/file_foo
$ cp -v foo* NEWDIR/
foo_file -> NEWDIR/foo_file
$ cp -v *foo* NEWDIR/
file_foo -> NEWDIR/file_foo
file_foo_file -> NEWDIR/file_foo_file
foo_file -> NEWDIR/foo_file
$ ls NEWDIR/
file_foo file_foo_file foo_file
回答by dough
Try this statement: cp *foo* /newdir
试试这个语句： cp *foo* /newdir
回答by mvds
If you are really concerned about the number of files (e.g. running in the millions) you could use:
如果您真的很关心文件的数量（例如运行数百万），您可以使用：
find . -type f -depth 1 -name "*foo*" -exec cp {} /otherdir \; -print
This doesn't use shell expansion, so you will not try to run a command with a million arguments. The -printgives you some indication of progress and can be left out. To simply list the files that are to be copied:
这不使用 shell 扩展，因此您不会尝试运行带有一百万个参数的命令。在-print为您提供了一些进展指示，并可以被排除在外。简单地列出要复制的文件：
find . -type f -depth 1 -name "*foo*"
回答by DreadPirateShawn
cp *foo* /path/to/separate_directory
If you want to validate the files that will be included first, the use:
如果要验证将首先包含的文件，请使用：
ls *foo*
This will confirm the files to be matched, then you can re-use the same pattern with the cp command to execute the copy.
这将确认要匹配的文件，然后您可以重新使用与 cp 命令相同的模式来执行副本。
