C++ 打印指针的值
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C++ print value of a pointer
提问by user69514
I have an array of double pointers, but every time I try do print one of the values the address gets printed. How do I print the actual value?
我有一个双指针数组，但是每次我尝试打印地址时都会打印一个值。如何打印实际值？
cout << arr[i] ? cout << &arr[i] ? they both print the address
cout << arr[i] ? cout << &arr[i] ? 他们都打印地址
Does anyone know?
有人知道吗？
回答by Matthew Flaschen
If it's really an array of (initialized) double pointers, i.e.:
如果它真的是一个（初始化的）双指针数组，即：
double *arr[] = ...
// Initialize individual values
all you need is:
所有你需要的是：
cout << *arr[i];
回答by Thomas Bonini
cout << *(arr[i]);
cout << *(arr[i]);
回答by Anatoly Fayngelerin
cout << *(arr[i]) will print the value.
cout << *(arr[i]) 将打印值。
回答by Jay Walker
If "arr" is declared as
如果“arr”被声明为
double* arr[..];
Then you would use:
然后你会使用：
cout << *(arr[i])
