遍历 SQL Server 中的字符串列表?

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时间:2020-09-01 04:43:39  来源:igfitidea点击:

Iterate through a list of strings In SQL Server?

sqlsql-servertsql

提问by KyloRen

How do you access the value within a list in T-SQL?

如何在 T-SQL 中访问列表中的值?

I have a SQL statement that loops through and counts how many times a value appears in a specific column in Table_1. Then it inserts the required values into their columns on Table_2or if the row dose not exist, it adds a new row and adds the necessary data.

我有一个 SQL 语句,它循环遍历并计算值在Table_1. 然后它将所需的值插入到它们的列中,Table_2或者如果该行不存在,它会添加一个新行并添加必要的数据。

I created the list or table to be exact,

确切地说,我创建了列表或表格,

DECLARE @MyList TABLE (Value NVARCHAR(50))
INSERT INTO @MyList VALUES ('Data1')
INSERT INTO @MyList VALUES ('Data2')
INSERT INTO @MyList VALUES ('Data3')
INSERT INTO @MyList VALUES ('Data4')
INSERT INTO @MyList VALUES ('Data5')
INSERT INTO @MyList VALUES ('Data6')
INSERT INTO @MyList VALUES ('Data7')
INSERT INTO @MyList VALUES ('Data8')

The statement works fine, but I have everything hardcoded and I want to add some dynamic data to be inserted, so I created a list of values (Strings). Now I can't access the values the way I though I could.

该语句工作正常,但我对所有内容进行了硬编码,并且我想添加一些要插入的动态数据,因此我创建了一个值列表(字符串)。现在我无法以我可以的方式访问这些值。

This is the whole statement,

这是整个声明,

DECLARE @cnt INT = 1;
DECLARE @MyList TABLE (Value NVARCHAR(50))
INSERT INTO @MyList VALUES ('Data1')
INSERT INTO @MyList VALUES ('Data2')
INSERT INTO @MyList VALUES ('Data3')
INSERT INTO @MyList VALUES ('Data4')
INSERT INTO @MyList VALUES ('Data5')
INSERT INTO @MyList VALUES ('Data6')
INSERT INTO @MyList VALUES ('Data7')
INSERT INTO @MyList VALUES ('Data8')

                        WHILE @cnt < 9
                        BEGIN

                            IF EXISTS (SELECT * FROM Staff_Manager.dbo.Staff_Count_TBL WHERE Staff_No = 3201 AND Year_D = 2016 AND Month_D = 6 AND Column_Index = @cnt)
                                BEGIN
                                  UPDATE Staff_Manager.dbo.Staff_Count_TBL 
                                            SET Column_Value = (
                                                 SELECT COUNT(*)  
                                                 FROM Staff_Manager.dbo.Staff_Time_TBL
                                                 WHERE Staff_No = 3201 AND Date_Data BETWEEN '2016/6/1' AND '2016/7/1' AND Info_Data = 'Data_1'
                                                 GROUP BY Staff_No, Info_Data),
                                                 Column_Value2 = 'Data1'
                                                 WHERE Staff_No = 3201 AND Year_D = 2016 AND Month_D = 6 AND Column_Index = @cnt
                                END
                            ELSE
                                BEGIN
                                   INSERT INTO Staff_Manager.dbo.Staff_Count_TBL 
                                        (Staff_No, Year_D, Month_D, Column_Index, Column_Value, Column_Value2)
                                        SELECT 3201, 2016, 6, @cnt, COUNT(*), 'Data1' 
                                             FROM Staff_Manager.dbo.Staff_Time_TBL
                                             WHERE Staff_No = 3201 AND Date_Data BETWEEN '2016/6/1' AND '2016/7/1' AND Info_Data = 'Data1' 
                                             GROUP BY Staff_No, Info_Data
                                END
                            SET @cnt = @cnt + 1
                        END

What I am trying to achieve is to loop through a list that has 8 items in it and enter those values into their corrosponding columns.

我想要实现的是循环遍历一个包含 8 个项目的列表,并将这些值输入到相应的列中。

Eg,

例如,

On this line I have hardcoded Data1,

在这一行我已经硬编码Data1

WHERE Staff_No = 3201 AND Date_Data 
       BETWEEN '2016/6/1' AND '2016/7/1' AND Info_Data = 'Data1'

What I am trying to do is this,

我想做的是这个,

WHERE Staff_No = 3201 AND Date_Data 
       BETWEEN '2016/6/1' AND '2016/7/1' AND Info_Data = @MyList[@cnt]

And this,

和这个,

SELECT 3201, 2016, 6, @cnt, COUNT(*), @MyList[@cnt] 
                     FROM Staff_Manager.dbo.Staff_Time_TBL                           
                     WHERE Staff_No = 3201 AND Date_Data 
                    BETWEEN '2016/6/1' AND '2016/7/1' AND Info_Data = @MyList[@cnt] 

But that does not work. After researching a little more, I found that T-SQL does not actually make a list , but a temp Table so to speak and you need to get the value from there. Unfortunately I can't seem to get anything to work.

但这不起作用。经过更多的研究,我发现 T-SQL 实际上并没有创建一个列表,而是一个临时表,可以这么说,你需要从那里获取值。不幸的是,我似乎无法得到任何工作。

I have an UPDATEand a INSERTstatement that I need to add the value from the list.

我有UPDATE一个INSERT声明,我需要从列表中添加值。

EDIT: Last minute code tweaking,

编辑:最后一分钟的代码调整,

DECLARE @cnt INT = 1;
DECLARE @MyList TABLE (Value NVARCHAR(50))
INSERT INTO @MyList VALUES ('Data1')
INSERT INTO @MyList VALUES ('Data2')
INSERT INTO @MyList VALUES ('Data3')
INSERT INTO @MyList VALUES ('Data4')
INSERT INTO @MyList VALUES ('Data5')
INSERT INTO @MyList VALUES ('Data6')
INSERT INTO @MyList VALUES ('Data7')
INSERT INTO @MyList VALUES ('Data8') 
INSERT INTO @MyList VALUES ('Data9')
INSERT INTO @MyList VALUES ('Data10')
INSERT INTO @MyList VALUES ('Data11')
INSERT INTO @MyList VALUES ('Data12')
INSERT INTO @MyList VALUES ('Data13')
INSERT INTO @MyList VALUES ('Data14')
INSERT INTO @MyList VALUES ('Data15')
INSERT INTO @MyList VALUES ('Data16')
INSERT INTO @MyList VALUES ('Data17')
INSERT INTO @MyList VALUES ('Data18')
INSERT INTO @MyList VALUES ('Data19')
INSERT INTO @MyList VALUES ('Data20')
INSERT INTO @MyList VALUES ('Data21')
INSERT INTO @MyList VALUES ('Data22')
INSERT INTO @MyList VALUES ('Data23')
INSERT INTO @MyList VALUES ('Data24')
INSERT INTO @MyList VALUES ('Data25')
INSERT INTO @MyList VALUES ('Data26')
INSERT INTO @MyList VALUES ('Data27')
INSERT INTO @MyList VALUES ('Data28')
INSERT INTO @MyList VALUES ('Data29')
INSERT INTO @MyList VALUES ('Data30')

DECLARE @COUNTER INT = 0;
DECLARE @MAX INT = (SELECT COUNT(*) FROM @MyList)
DECLARE @VALUE VARCHAR(50);


                        WHILE @cnt <= @MAX  
                        BEGIN
                        SET @VALUE = (SELECT Value FROM @MyList 
                            ORDER BY 1 OFFSET @COUNTER 
                            ROWS FETCH NEXT 1 ROWS ONLY);


                            PRINT @cnt
                            PRINT @VALUE
                            PRINT @COUNTER

                            IF EXISTS (SELECT * FROM Staff_Manager.dbo.Staff_Count_TBL WHERE Staff_No = 3005 AND Year_D = 2016 AND Month_D = 6 AND Column_Index = @cnt)
                                BEGIN
                                  UPDATE Staff_Manager.dbo.Staff_Count_TBL 
                                            SET Column_Value = (
                                                 SELECT COUNT(*)  
                                                 FROM Staff_Manager.dbo.Staff_Time_TBL
                                                 WHERE Staff_No = 3005 AND Date_Data BETWEEN '2016/6/1' AND '2016/7/1' AND Info_Data = @value
                                                 GROUP BY Staff_No, Info_Data),
                                                 Column_Value2 = @value
                                                 WHERE Staff_No = 3005 AND Year_D = 2016 AND Month_D = 6 AND Column_Index = @cnt
                                END
                            ELSE
                                BEGIN
                                   INSERT INTO Staff_Manager.dbo.Staff_Count_TBL 
                                        (Staff_No, Year_D, Month_D, Column_Index, Column_Value, Column_Value2)
                                        SELECT 3005, 2016, 6, @cnt, COUNT(*), @value 
                                             FROM Staff_Manager.dbo.Staff_Time_TBL
                                             WHERE Staff_No = 3005 AND Date_Data BETWEEN '2016/6/1' AND '2016/7/1' AND Info_Data = @value 
                                             GROUP BY Staff_No, Info_Data
                                END
                            SET @cnt = @cnt + 1
                            SET @COUNTER = @COUNTER + 1
                        END

回答by Zein Makki

What you created is not a list but a table variable. So how to Iterate over a table. Below is a simple example and I think you can proceed after if you understand it:

您创建的不是列表而是表变量。那么如何迭代一个表。下面是一个简单的例子,如果你理解了,我认为你可以继续:

(Note: Cursors are not efficient when it comes to performance and large tables)

(注意:游标在性能和大表方面效率不高)

DECLARE @MyList TABLE (Value NVARCHAR(50))
INSERT INTO @MyList VALUES ('Data1')
INSERT INTO @MyList VALUES ('Data2')
INSERT INTO @MyList VALUES ('Data3')
INSERT INTO @MyList VALUES ('Data4')
INSERT INTO @MyList VALUES ('Data5')
INSERT INTO @MyList VALUES ('Data6')
INSERT INTO @MyList VALUES ('Data7')
INSERT INTO @MyList VALUES ('Data8')

DECLARE @value VARCHAR(50)

DECLARE db_cursor CURSOR FOR  
SELECT Value FROM @MyList
OPEN db_cursor   
FETCH NEXT FROM db_cursor INTO @value   

WHILE @@FETCH_STATUS = 0   
BEGIN   
       PRINT @value

       -- PUT YOUR LOGIC HERE
       -- MAKE USE OR VARIABLE @value wich is Data1, Data2, etc...

       FETCH NEXT FROM db_cursor INTO @value   
END   

CLOSE db_cursor   
DEALLOCATE db_cursor

Prints:

印刷:

Data1
Data2
Data3
Data4
Data5
Data6
Data7
Data8

So you have inside @value variable Data, Data2.. etc . I think this solves your problem.

所以你有 @value 变量DataData2.. 等。我认为这可以解决您的问题。

Alternative way is using a WHILEloop + OFFSET+ FETCH NEXT:

另一种方法是使用WHILE循环OFFSET++ FETCH NEXT

DECLARE @MyList TABLE (Value NVARCHAR(50))
INSERT INTO @MyList VALUES ('Data1')
INSERT INTO @MyList VALUES ('Data2')
INSERT INTO @MyList VALUES ('Data3')
INSERT INTO @MyList VALUES ('Data4')
INSERT INTO @MyList VALUES ('Data5')
INSERT INTO @MyList VALUES ('Data6')
INSERT INTO @MyList VALUES ('Data7')
INSERT INTO @MyList VALUES ('Data8')

DECLARE @COUNTER INT = 0;
DECLARE @MAX INT = (SELECT COUNT(*) FROM @MyList)
DECLARE @VALUE VARCHAR(50);

WHILE @COUNTER < @MAX
BEGIN

SET @VALUE = (SELECT VALUE FROM
      (SELECT (ROW_NUMBER() OVER (ORDER BY (SELECT NULL))) [index] , Value from @MyList) R 
       ORDER BY R.[index] OFFSET @COUNTER 
       ROWS FETCH NEXT 1 ROWS ONLY);

PRINT @VALUE

SET @COUNTER = @COUNTER + 1

END

You get the same result

你得到同样的结果